answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BARSIC [14]
2 years ago
5

A force of 8 N is used to drag a chair 2.5 metres across a room. Calculate the work done to move the chair.

Physics
2 answers:
NNADVOKAT [17]2 years ago
8 0

Answer:

Explanation:

GIVEN

Force (F) = 8 N

Distance (d) = 2.5 metres

Work done = ?

WE know we have the formula

work done = F * d

Work done = 8 * 2.5

                   = 20 Joule

Hope it helps :)

serg [7]2 years ago
8 0

Answer:its 20 Joule

Explanation:

You might be interested in
There are two different size spherical paintballs and the smaller one has a diameter of 5 cm and the larger one is 9 cm in diame
slavikrds [6]

Answer:

145.8 cm³ of paint

Explanation:

d₁ = Smaller diameter paintball = 5 cm

d₂ = Larger diameter paintball = 9 cm

V₂ = Volume of larger diameter paintball

Volume of smaller diameter paintball

V_1=\frac{4}{3}\pi r_1^3\\\Rightarrow V_1=\frac{4}{3}\pi \left(\frac{d_1}{2}\right)^3\\\Rightarrow V_1=\frac{4}{24}\pi d_1^3

Similarly

V_2=\frac{4}{24}\pi d_2^3

Dividing the above two equations, we get

\frac{V_1}{V_2}=\frac{d_1^3}{d_2^3}\\\Rightarrow V_2=\frac{V_1}{\frac{d_1^3}{d_2^3}}\\\Rightarrow V_2=\frac{28}{\frac{125}{729}}\\\Rightarrow V_2=163.296\ cm^3

∴ The larger one hold 163.296 cm³ of paint

5 0
2 years ago
A hungry 169169 kg lion running northward at 77.377.3 km/hr attacks and holds onto a 31.731.7 kg Thomson's gazelle running eastw
navik [9.2K]

Answer:  75,242.9 m/s

Explanation:

from the question we are given the following parameters

mass of Lion (ML) = 169,169 kg

velocity of lion (VL) = 777,377.7 m/s

mass of Gazelle (Mg) = 31,731.7 kg

velocity of Gazelle (Vg) = 63,863.8 kg

mass of Lion and Gazelle (M) = 200,900.7 kg

velocity of Lion and Gazelle (V) = ?

The first figure below shows the motion of the Lion and Gazelle with their direction.

The second diagram shows the motion of the Lion and Gazelle with their directions rearranged to form a right angle triangle.

from the triangle formed we can get the velocity of the Lion and Gazelle immediately after collision using their momentum and Phytaghoras theorem

momentum = mass x velocity

momentum of the Lion = 169,169 x 77,377.3 = 13,089,840,463.7 kgm/s

momentum of the Gazelle = 31,731.7 x 63,863.8 = 2,026,506,942.46 kgm/s

momentum of the Lion and Gazelle = 200,900.7  x V

now applying Phytaghoras theorem we have

13,089,840,463.7 + 2,026,506,942.46 =  200,900.7 x V

15,116,347,406.16 = 200,900.7 x V

V = 75,242.9 m/s

7 0
2 years ago
Read 2 more answers
A 10.0 cm3 sample of copper has a mass of 89.6
Romashka-Z-Leto [24]
Density is mass divides by volume, so
89.6g / 10cm^3 =8.96g /cm^3

*cm^3 is a standard unit of volume*
4 0
2 years ago
Every spring has an equilibrium position. Which statements describe a spring at its equilibrium position? Check all that
alexgriva [62]

Answer:

The elastic potential energy is zero.

The net force acting on the spring is zero.

Explanation:

The equilibrium position of a spring is the position that the spring has when its neither compressed nor stretched - it is also called natural length of the spring.

Let's now analyze the different statements:

The spring constant is zero.  --> false. The spring constant is never zero.

The elastic potential energy is at a maximum  --> false. The elastic potential energy of a spring is given by

E=\frac{1}{2}kx^2

where k is the spring constant and x the displacement. Therefore, the elastic potential energy is maximum when x, the displacement, is maximum.

The elastic potential energy is zero.  --> true. As we saw from the equation above, the elastic potential energy is zero when the displacement is zero (at the equilibrium position).

The displacement of the spring is at a maxi num  --> false, for what we said above

The net force acting on the spring is zero. --> true, as the spring is neither compressed nor stretched

8 0
2 years ago
Read 2 more answers
A red ball, initially at rest, is simultaneously hit by a blue ball traveling from west to east at 5 m/s and a green ball travel
andrezito [222]

Answer:

C. Between North and West

Explanation:

Since all have equal masses and the red ball and green ball are moving in south and east direction, the blue ball would most likely be moving between the north and West direction.

8 0
2 years ago
Other questions:
  • The total energy of a 0.050 kg object travelling at 0.70 c is
    13·1 answer
  • Bob has a brother, jim, who has a daughter named bertha. Bertha's daughter, jennifer, has a sister named penny. which of the fol
    5·2 answers
  • Please help! Kiki makes a table to compare the particles in a magnesium atom to those in a magnesium ion. She knows that a magne
    5·2 answers
  • Two students are working together on an experiment that measures the effect of different liquid fertilizers on the thickness of
    14·2 answers
  • A spaceship is travelling at 20,000.0 m/s. After 5.0 seconds, the rocket thrusters are turned on. At the 55.0 second mark, the s
    9·1 answer
  • Points a and b lie in a region where the y-component of the electric field is Ey=α+β/y2. The constants in this expression have t
    9·1 answer
  • A proton is released from rest at the origin in a uniform electric field that is directed in the positive xx direction with magn
    10·1 answer
  • If I0 is the intensity of the unpolarized light incident on the first polarizer, and I1 and I2 denote the intensity of the light
    14·1 answer
  • The inductor in a radio receiver carries a current of amplitude 200 mA when a voltage of amplitude 2.40 V is across it at a freq
    13·1 answer
  • An ideal monatomic gas initially has a temperature of T and a pressure of p. It is to expand from volume V1 to volume V2. If the
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!