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2 years ago

An object moving at a velocity of 32m/s slows to a stop in 4 seconds. What was its acceleration?

Physics

2 answers:

Romashka [77]2 years ago

6 0

Answer:

8m/s

Explanation:

a=d/t

a=32/4

a=8 m/s

LiRa [457]2 years ago

5 0

Answer:

-8m/s^2

Explanation:

initial velocity(u)=32m/s

Final velocity(v)=0

Time(t)=4seconds

Acceleration(a)=?

v=u+axt

0=32+ax4

-32=4a

a=-32/4

a=-8m/s^2

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Answer:

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Explanation:

Given that,

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Answer:

Explanation:

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= $\frac{2D}{V(1 - \frac{v^2}{V^2}) }$

= The denominator contains a factor

$1-\frac{v^2}{V^2}$

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2 years ago

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Black_prince [1.1K]

Answer:

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