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Ivan
2 years ago
4

Quiz3: Identical 2.0 µC charges are located on the vertices of a square with sides that are 2.0 m in length. Determine the infin

ity) at the center of the square. electric potential (relative to zero at
Physics
1 answer:
EleoNora [17]2 years ago
7 0

Answer:

V = 50.91 kV  

Explanation:

given data

charges = 2.0 µC  =  2.0 × 10^{-6}  C

length of a =2.0 m

solution

we get here first distance by corner to center that is express as

r = a ÷ √2     ...............1

put here value and we get

r = 2.0 ÷ √2

r = √2 m

and

here potential at distance r due the point charge (q) is express as

V = q ÷ ( 4 π εo r  )     ...............2

so 4 charges the total potential will be as

V = 4q ÷ ( 4 π εo r  )    ...............3

and here 1 ÷ (4 π εo ) = 9.0 × 10^{9} N m²/C²

so that

total potential at the center will be

V = ( 4 ×  9.0 × 10^{9}  × 2.0 × 10^{-6} )  ÷ √2

solve it and we will get

V = 50.91 kV  

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Fed [463]
I assume the x-y axis are tilted such that the x-axis is parallel to the surface of the hill while the y-axis is perpendicular to it.

In this case, the x-component of the weight is given by:
W_x =mg \sin \theta
where
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Substituting numbers into the formula, we find
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6 0
2 years ago
9ma electric current is flowing through a conducting wire , then the number of electron passing through it in 3 min is
Leviafan [203]

Answer:

1.0125 x 10^19

Explanation:

current flowing through conductive wire= 9mA = 9 x 10^ -3 A

charge passing per 3 min

Q = It

= 9 x 10^ -3 x (3 x 60)

= 1.620 C

no of electrons in charge

Q = ne

1.620 = n x 1.6 x 10 ^ -19

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2 years ago
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Answer:

1 ) Electrons are less massive than than atomic nuclei.

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2 years ago
A typical adult human has a mass of about 70 kg.
Misha Larkins [42]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
a. <span>FM GmMmr2
</span>= 6.67 x 10-11N.m2kg27 .35 x 1022 kg 70 kg 3.78 x 108 m2 
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b. </span><span>FE GmEmr2
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3 0
2 years ago
Mt. Asama, Japan, is an active volcano complex. In 2009, an eruption threw solid volcanic rocks that landed far from the crater.
solong [7]

Answer:u=97.41m/s

Explanation:

Given

inclination \theta =58.7^{\circ}C

Horizontal distance travel by Particle d=1200 m

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y=u\sin \theta +\frac{at^2}{2}

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t=\frac{x}{u\cos \theta }

put value of t in equation 1

y=u\sin \theta \times \frac{x}{u\cos \theta }-\frac{g}{2}\times (\frac{x}{u\cos \theta })^2

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\frac{gx^2}{2u^2\cos ^2\theta }=x\tan \theta -y

u^2=\frac{gx^2}{2cos^2\theta (x\tan \theta -y)}

u=\sqrt{\frac{gx^2}{2cos^2\theta (x\tan \theta -y)}}

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u^2=\frac{18.154}{2753.65}\times 1200^2

u=97.41 m/s

6 0
2 years ago
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