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Virty [35]
2 years ago
13

5. A wave with peaks separated by .34 m has a wavelength of ________________m.

Physics
1 answer:
Eduardwww [97]2 years ago
8 0

Answer: 0.17 I think

Explanation:

I asked a doctor

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A 4.0 kg block is resting on a rough horizontal table. The coefficient of static friction us is 0.60. The static friction betwee
professor190 [17]

Answer: 24 N

Explanation:

Given that the

Mass m = 4 kg

Coefficient of friction (μ) = 0.60

To calculate the static friction between the block and the table before any attempted motion, you will use the formula; F = (μ)N

Where

F = static friction

N = normal reaction = mg

g = acceleration due to gravity = 9.8 m/^2

Substitutes m, g and (μ) into the formula

F = 0.6 × 4 × 9.8

F = 23.52 N

Therefore, the static friction between the block and the table before any attempted motion is 24 N approximately.

6 0
2 years ago
A 0.10 kg piece of copper at an initial temperature of 95°c is dropped into 0.20 kg of water contained in a 0.28 kg aluminum cal
DedPeter [7]
<span>(cp of Copper = 387J / kg times degrees C; cp of Aluminum = 899 J / kg times degrees C; cp of Water = 4186J / kg times degrees C)
</span> Use the law of conservation of energy and assuming no heat loss to the surroundings, then 
 <span>Heat given up by copper = heat absorbed by water + heat absorbed by calorimeter 
</span><span> Working formula is 
</span> <span>Q = heat = MCp(delta T) 
</span><span> where 
</span><span> M = mass of the substance 
</span><span> Cp = specific heat of the substance 
</span><span> delta T = change in temperature 
</span> Heat given up by copper = 0.10(387)(95 - T) 
<span> Heat absorbed by water = 0.20(4186)(T - 15) 
</span><span> Heat absorbed by calorimeter = 0.28(899)(T - 15) 
</span> where 
<span> T = final temperature of the system 
</span><span> Substituting appropriate values, 

</span> 0.10(387)(95 - T) = 0.20(4186)(T - 15) + 0.28(899)(T - 15) 
<span> 38.7(95 - T) = 1088.92(T - 15) 
</span><span> 3676.50 - 38.7T = 1088.92T - 16333.8 
 </span><span>1127.62T = 20010.3 
</span><span> T = 17.75 C </span>
8 0
2 years ago
You decide to work at a heart rate of 150 instead of 120. What area of F.I.T.T. did you change?
Rina8888 [55]

Key concepts

Heart rate

Exercising

The heart

Cardiovascular system

Health

Introduction

As Valentine's Day approaches, we're increasingly confronted with "artistic" images of the heart. Real hearts hardly resemble to two-lobed shapes adorning cards and candy boxes this time of year. And the actual shape of the human heart is important for its function of supplying blood to the entire body. You have likely noticed that your heart beats more quickly when you exercise. But have you ever taken the time to observe how long it takes to return to its normal rate after you're done exercising? In this science activity you'll get to do some exercises to explore your own heart-rate recovery time.

Background

Your heart is continuously beating to keep blood circulating throughout your body. Its rate changes depending on your activity level; it is lower while you are asleep and at rest and higher while you exercise—to supply your muscles with enough freshly oxygenated blood to keep the functioning at a high level. Because your heart is also a muscle, exercise, in turn, helps keep it healthy. The American Heart Association recommends that a person does exercise that is vigorous enough to raise their heart rate to their target heart-rate zone—50 percent to 85 percent of their maximum heart rate, which is 220 beats per minute (bpm) minus their age for adults—for at least 30 minutes on most days, or about 150 minutes a week in total. So for a 20-year-old, the maximum heart rate would be 200 bpm, with a target heart-rate zone of 100 to 170 bpm. (For those 19 or younger, target zones can vary more than they do for adults.)

i think it will help you...if it help you ...please mark brainless

8 0
2 years ago
Before leaving the house in the morning, you plop some stew in your slow cooker and turn it on Low. The slow cooker has a 160 Oh
guajiro [1.7K]

Answer:

Total charge flow through the cooker is 21600 C

Explanation:

As we know that the current flow through the cooker is given by Ohm's law

here it is given as

V = i R

i = \frac{V}{R}

i = \frac{120}{160}

i = \frac{3}{4} A

now the charge flow through it is given as

Q = i t

total time is t = 8 hours

Q = \frac{3}{4}(8 \times 60 \times 60)

Q = 21600 C

7 0
2 years ago
A box is at rest on a ramp at an incline of 22°. The normal force on the box is 538 N.
fomenos

Answer: 580 N

Refer to attached figure.

The angle of inclination is 22 degrees

weight (gravitational force) acts downwards.

Normal force is a contact force which acts perpendicular to the point of contact.

The horizontal component (mg cos 22 ) balances the normal force and the vertical component balances the frictional force.

Gravitational force on an object = mg

The normal force N= mg cos 22

\Rightarrow mg =\frac{N}{cos22}=\frac{538 N}{0.927}=580 N





8 0
2 years ago
Read 2 more answers
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