Question

Mr. Dunn drives 64.8km from work at a speed of 48km/h. Mrs. Dunn drives 81.2km from work

Answer 1

Answer:

i) Mr. Dunn arrives to home first.

ii) 3 min

Explanation:

i. To find who arrives first to home you calculate the time, by using the following formula:

$t=\frac{x}{v}$

x: distance

v: velocity

Mr. Dunn:

$t=\frac{64.8km}{48km/h}=1.35h$

Mrs. Dunn:

$t=\frac{81.2km}{58km/h}=1.4h$

Hence, Mr. Dunn arrives to home first.

ii. To calculate the difference in minutes, you convert hours to minutes:

$1.35h*\frac{60min}{1h}=81min\\\\1.40h*\frac{60min}{1h}=84min\\\\\Delta\ t=(84-81)min=3min$

the difference between the times is 3min