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BartSMP [9]
1 year ago
10

The box plot compares the number of events that Mrs. Cai’s and Mr. Roland’s classes won over the last 10 years on the school’s f

ield day.
A number line goes from 0 to 10. Mrs. Cai's class's whiskers range from 0 to 8, and the box ranges from 2 to 4. A line divides the box at 3. Mr. Roland's class's whiskers range from 1 to 8, and the box ranges from 4 to 7. A line divides the box at 5.
Based on the data in the box plots, what is the best evidence to show which class has had greater success on field day over the last 10 years?

Mrs. Cai’s class was more successful because her interquartile range was less spread out.
Mrs. Cai’s class was more successful because she had the greater total spread.
Mr. Roland’s class was more successful because his class always won at least one event.
Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.
Mathematics
2 answers:
zimovet [89]1 year ago
9 0

Answer:

D

Step-by-step explanation:

Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.

nata0808 [166]1 year ago
7 0

Answer:

D. Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.

Step-by-step explanation:

Mrs. Cai's class's box ranges from 2 to 4, that is, her class’s upper quartile is 4.

Mr. Roland's class's box ranges from 4 to 7, that is, his class’s lower quartile 4.

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Submarine: -730
Airplane: 9,144
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|d|: absolute value
The vertical distance between the submarine and airplane is 9,874 meters.
4 0
2 years ago
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Find the value of y for a given value of x, if y varies directly with x.
stepan [7]

Answer:

5.46

Step-by-step explanation:

3.24/5.4 = y/9.1

7 0
2 years ago
Let p denote the proportion of students at a particular university that use the fitness center on campus on a regular basis. For
9966 [12]

Answer:

a) P-value = 0.0968

b) P-value = 0.2207

c) P-value = 0.0239

d) P-value = 0.0040

e) P-value = 0.5636

Step-by-step explanation:

As the hypothesis are defined with a ">" sign, instead of an "≠", the test is right-tailed.

For this type of test, the P-value is defined as:

P-value=P(z>z^*)

being z* the value for each test statistic.

The probability P is calculated from the standard normal distribution.

Then, we can calculate for each case:

(a) 1.30

P-value=P(z>1.30) = 0.0968

(b) 0.77

P-value=P(z>0.77) = 0.2207

(c) 1.98

P-value=P(z>1.98) = 0.0239

(d) 2.65

P-value=P(z>2.65) = 0.0040

(e) −0.16

P-value=P(z>-0.16) = 0.5636

7 0
2 years ago
Anita had $400 in her savings account when she went to college. Her parents will add $200 to her account each month. Miguel had
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2 years ago
For a specific location in a particularly rainy city, the time a new thunderstorm begins to produce rain (first drop time) is un
ikadub [295]

Answer:

b) 0.0608

Step-by-step explanation:

As it is mentioned that the next two days i.e 24 hours, the probability of the rain is uniformly distributed

Therefore the rain probability is

= \frac{T}{24}

where,

T = Length of the time interval

Plus, as we know that rain is independent

So let us assume the rain between the 8: 40 AM and 2: 35 PM on single day is P1 and the time interval is 5 hours 55 minutes

i.e

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So, P1 should be

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= 0.2465

Now we assume the probability of rain on day 2 is P2

So it would be same  i.e 0.2465

Since these events are independent

So, the total probability is

= 0.2465 \times 0.2465

= 0.0608

Hence, the b option is correct

3 0
2 years ago
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