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Katyanochek1 [597]
2 years ago
12

n the calibration step of a thermochemistry experiment, a current of 124\text{ mA}124 mA, from a 24.0\text{ V}24.0 V source was

allowed to flow through the electrical heater for 219\text{ s}219 s and was found to result in an increase in the temperature of the calorimeter and its contents of +1.39\text{ K}+1.39 K. Given that the energy supplied by an electrical circuit is the voltage multiplied by the current, multiplied by the time, what is the heat capacity of the calorimeter and its contents?
Physics
1 answer:
BabaBlast [244]2 years ago
8 0

Answer: C = 468.88 J/kgk

Explanation: Given that the

Current I = 124 mA

Voltage V = 24 V

Time t = 219 s

Change in temperature Ø = 1.39 K

Heat energy = mcØ

Also,

Heat energy = IVt

Where c = specific heat capacity

IVt = mcØ

Let assume that the mass is negligible or a unit mass = 1kg

124 × 10^-3 × 24 × 219 = 1.39c

C = 651.744/1.39

C = 468.88 J/kgk

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AVprozaik [17]

Answer:

Sonia will experience repulsion in two balloons

Explanation:

Here when we rub the balloon with the woolen cloth then due to friction between the cloth and balloon electrons from balloon will transfer to woolen cloth.

Due to transfer of electron the balloon will get positive charge which is given by

Q = Ne

so here since both balloons are rubbed against woolen cloth so both balloon will get some positive charge

now we know by the property of charge that two similar charges will always repel each other so here two balloons will repel each other after they rubbed against woolen cloth.

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2 years ago
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The diagram shows movement of thermal energy. At bottom a fire has red curved lines labeled Y with arrowheads pointing upward to
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Answer:

X and Z

Explanation:

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Three wires are made of copper having circular cross sections. Wire 1 has a length l and radius r. Wire 2 has a length l and rad
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Explanation:

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4 0
2 years ago
On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max
sesenic [268]

Work done by a given force is given by

W = F.d

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = W_1 = Fdcos\theta

W_1 = 12*5cos15

W_1 = 57.96 J

Now similarly work done by frictional force

W_2 = Fdcos\theta

W_2 = 4*5cos180

W_2= -20 J

Now total work done on sled

W_{net}= W_1 + W2

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7 0
2 years ago
A 1500 kg car traveling at 20 m/s suddenly runs out of gas while approaching the valley shown in the figure. The alert driver im
geniusboy [140]

Answer:

v_f = 17.4 m / s

Explanation:

For this exercise we can use conservation of energy

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final point. Arriving at the gas station

         Em_f = K + U = ½ m v_f ² + m g y₂

energy is conserved

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         ½ m v₀ ² + m g y₁ = ½ m v_f ² + m g y₂

        v_f ² = v₀² + 2g (y₁ -y₂)

         

we calculate

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         v_f = 17.4 m / s

8 0
2 years ago
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