Help!!!! A loop of area 0.100 m^2 is oriented at 15.5 degree angle to a 0.500 T magnetic field. It rotates until it is at a 45.0
1 answer:
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To solve this problem it is necessary to use the given proportions of power and energy, as well as the energy conversion factor in Jules to Calories.
The power is defined as the amount of energy lost per second and whose unit is Watt. Therefore the energy loss rate given in seconds was
The rate of energy loss per day would then be,
That is to say that Energy in Jules per lost day is 5356800J
By definition we know that
In this way the energy in Cal is,
The number of kilocalories (food calories) must be 1279.694 KCal
Answer:
7.3 kg m/s
Explanation:
First of all, let's calculate the gravitational potential energy of the stone as it reaches its highest point:
For the law of conservation of energy, this is equal to the initial kinetic energy of the stone at ground level (where the potential energy is zero), just after the stone leaves your hand:
From this equation we can find the velocity of the stone as it leaves your hand:
The initial velocity of the stone (before leaving your hand) is zero:
The impulse received by the stone is equal to its change in momentum, so: