El superóxido de potasio, KO2, se emplea en máscaras de respiración para generar
1 answer:
Answer:
Reactivo límite: Superóxido de potasio.
Moles de oxígeno producidas:
Explanation:
Hola,
En este caso, considerando la reacción química llevada a cabo:
Es posible identificar el reactivo límite calculando las moles de superóxido de potasio que serían consumidas por 0.10 mol de agua por medio de la relación molar 4 a 2 que hay entre ellos:
Así, dado que solo hay 0.15 mol the superóxido de potasio, podemos decir que este es el reactivo límite. Luego, calculamos las moles de oxígeno producidas, considerando la relación molar 4 a 3 que hay entre el superóxido y el oxígeno:
Best regards.
You might be interested in
Answer:
The correct option is option (D).
Therefore the concentration of is 1.8×10⁻¹⁰ M and it is basic in nature.
Explanation:
List of pH:
- If pH of a solution is 7, then solution is neutral.
- If pH of a solution is grater than 7, then solution is basic.
- If pH of a solution is less than 7, then solution is acidic.
pH of a solution is = - log₁₀[H₃O⁺]
We know that,
[H₃O⁺][OH⁻] = =
(at 25°C)
Taking log both sides
log ([H₃O⁺][OH⁻]) =log =log
⇒log[H₃O⁺]+log[OH⁻] = log = -14 log 10
[since log(mn)= log m + log n, ]
⇒ - log[H₃O⁺] - log[OH⁻] = - (-14) [ log 10 =1]
⇒pH+pOH =14.
Given that,
The concentration of OH⁻ is 5.5 × 10⁻⁵ M
[H₃O⁺][OH⁻] = =
⇒[H₃O⁺] 5.5 × 10⁻⁵ M=10⁻¹⁴
⇒[H₃O⁺] = 1.8×10⁻¹⁰ M
Now check the pH of the solution.
[H₃O⁺] = 1.8×10⁻¹⁰
Taking log both sides
log [H₃O⁺] =log( 1.8×10⁻¹⁰)
⇒ -log [H₃O⁺] = - log( 1.8×10⁻¹⁰)
⇒ pH = - log( 1.8×10⁻¹⁰)
⇒ pH =9.7.
So the nature of solution is basic.
Therefore the concentration of is 1.8×10⁻¹⁰ M and it is basic in nature.
Answer:
Explanation:
Hello,
a) In this case, since the heat associated with the dissolution of ammonium nitrate is positive, such reaction is endothermic as it absorbs heat.
b) Now, for computing the temperature once the dissolution is done, we apply (considering that it is a cooling process):
Nonetheless, we should first compute the moles of the mixture as:
Thus, the total absorbed heat is:
Now, the temperature is:
Best regards.