Question

Si se pesan 0.456 gramos de NaOH y se disuelven en 100.0 ml de solución. ¿cuál es la molaridad?

Answer 1

Answer:

$M=0.114M$

Explanation:

Hello,

In this case, we define the molarity as the ratio between the moles of the solute, NaOH here, and the volume of the solution in litres:

$M=\frac{n}{V}$

For that reason, one must first compute the moles of sodium hydroxide by using its molar mass of 40 g/mol:

$n=\frac{0.456g}{40g/mol}=0.0114mol$

Then, the volume in litres:

$V=100.0mL*\frac{1L}{1000mL} =0.1000L$

Finally we compute the molarity:

$M=\frac{0.0114mol}{0.1000L}\\ \\M=0.114M$

Best regards.