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2 years ago

13

Planet X has a magnetic field with strength 0.80 G in the southern direction. When a probe is placed 30 mm east of a vertical wi

re it measures a field of 0.60 G in the southern direction. What would a probe read if placed 10 mm east of the vertical wire?
A. 0.20 G towards the south
B. 0.60 G towards the north
C. 1.00 G towards the south
D. 1.40 G towards the north

1 answer:

sleet_krkn [62]2 years ago

8 0

0.20 G towards the south

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In a fast-pitch softball game the pitcher is impressive to watch, as she delivers a pitch by rapidly whirling her arm around so

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Answer:

(a) 181.05 m/s²

(b) 13.2°

Explanation:

Given:

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Angular speed (ω) = 17.0 rad/s

(a)

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Plug in the given values and solve for $a_r$ . This gives,

$a_r=(17.0\ rad/s)^2\times (0.610\ m)\\\\a_r=289\times 0.610\ m/s^2\\\\a_r=176.29\ m/s^2$

Now, tangential acceleration is given by the formula:

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Plug in the given values and solve for $a_t$ . This gives,

$a_t=(0.610\ m)(67.6\ rad/s^2)\\\\a_t=41.236\ m/s^2$

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(b)

Angle of total acceleration relative to radial direction is given by the formula:

$\theta=\tan^{-1}(\frac{a_t}{a_r})\\\\\theta=\tan^{-1}(\frac{41.236}{176.29})\\\\\theta=13.2\°$

Therefore, the total acceleration makes an angle of 13.2° relative to radial direction.

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2 years ago

Part A At t tt = 2.0 s s , what is the particle's position? Express your answer to two significant figures and include the appro

mars1129 [50]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The particle's position is $x_{2} = 10 m$

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Explanation:

From the question we are told that

$x = 2m$ at $t_o = 0 \ sec$

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Now the acceleration which is the slope of the graph is mathematically represented as

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2 years ago

A radioactive substance decays according to the formula w = 20e¡kt grams where t is the time in hours. a find k given that after

blagie [28]

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2 years ago

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vagabundo [1.1K]

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Similarly, the doppler shift in frequency is the frequency of sound heard by car B which is f' = 1140 Hz. And v is the speed of sound that is v = 343 m/s

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2 years ago