Question

In a titration, 5.0 ml of a 2.0 M NaOH (aq) solutions exactly neutralizes 10.0 ml of an HCL (aq) solution. what is the concentration of the HCl (aq) solution?

Answer 1

Answer:

$M_{acid}=1.0M$

Explanation:

Hello,

In this case, since the reaction between HCl and NaOH is:

$NaOH+HCl\rightarrow NaCl+H_2O$

We notice a 1:1 molar ratio between the acid and the base, for that reason, in the equivalent point we find:

$n_{acid}=n_{base}$

Thus, in terms of concentrations, we have:

$M_{acid}V_{acid}=M_{base}V_{base}$

Hence, we solve for the concentration of the acid to obtain:

$M_{acid}=\frac{M_{base}V_{base}}{V_{acid}} =\frac{2.0M*5.0mL}{10.0mL}\\ \\M_{acid}=1.0M$

Regards.