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alina1380 [7]
2 years ago
11

A school class went on a field trip to see a magician perform there were 17 females 20 males in the class the magicians randomly

selected a volunteer from the audience in which had 52 females and 68 males given that the randomly selected audience member is a student from the class which equation can be used to find the probability p that the perdimos also a female?please help does anyone know the answer
Mathematics
2 answers:
8090 [49]2 years ago
3 0

Answer:

P(A) = 37/100, P(A) = 37%

Step-by-step explanation:

Probability of an event = \frac{Number of favorable outcomes}{Total number of outcomes}

stira [4]2 years ago
3 0

Answer:

P=(17/20)/(52/68)

Step-by-step explanation:

I think that's the answer, I don't know for sure

Obviously, it is not (17/120)/(37/120) cause 37 are the males but its asking for the probability for the females

and it wouldn't be any of the multiplying equations cause we need the chances to grow not decrease

I know you guys will find a way to prove me wrong, but as I said before its just a guess

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Answer:

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2 years ago
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martin will roll a number of cube 150 times.The number cube is labeled 1 to 6.How many times could Martin expect to roll a numbe
olga_2 [115]
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7 0
2 years ago
Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

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2 years ago
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