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blsea [12.9K]
2 years ago
3

Joe is considering pursuing an MBA degree. He has applied to two different universities. The acceptance rate for applicants with

similar qualifications is 25 percent for University A and 40 percent for University B. What is the probability that Joe will be accepted at one, and only one, university
Mathematics
1 answer:
Olegator [25]2 years ago
4 0

Answer:

The probability that Joe will be accepted at one, and only one, university is 0.45 or 45%.

Step-by-step explanation:

We are given that Joe is considering pursuing an MBA degree. He has applied to two different universities.

The acceptance rate for applicants with similar qualifications is 25 percent for University A and 40 percent for University B.

Let the probability that Joe will be accepted for University A = P(A) = 0.25

Probability that Joe will be accepted for University B = P(B) = 0.40

Now, Probability that Joe will be accepted at one, and only one, university is given by ;

Accepted for University A but not for University B + Accepted for University B but not for University A

=  [P(A) \times (1 - P(B))] + [P(B) \times (1 - P(A))]

=  (0.25 \times 0.60) + (0.40 \times 0.75)

=  0.15 + 0.30 = 0.45

Hence, the probability that Joe will be accepted at one, and only one, university is 0.45.

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6. Charlie can spend up to $8 on lunch. He wants to buy a tuna sandwich, a bottle of
PilotLPTM [1.2K]

Answer:

The maximum number of pounds of potato salad that Charlie can buy is 0.375

Step-by-step explanation:

see the attached figure to better understand the problem

Let

a ----> the cost of one tuna sandwich

b ----> the cost of a bottle of apple juice

c ----> the cost per pound of potato salad

x ----> pounds of potato salad

we have

a=\$4.25

b=\$2.25

c=\$4.00/lb

we know that

He wants to buy a tuna sandwich, a bottle of  apple juice, and x pounds of potato salad and can spend up to $8

The inequality that represent this situation is

a+b+cx \leq 8

substitute the given values

4.25+2.25+4.00x \leq 8

Solve for x

Combine like terms

6.50+4.00x \leq 8

Subtract 6.50 both sides

4.00x \leq 8-6.50

4.00x \leq 1.50

Divide by 4 both sides

x \leq 1.50/4.00

x \leq 0.375\ lbs

therefore

The maximum number of pounds of potato salad that Charlie can buy is 0.375

3 0
2 years ago
What is the simplified value of the expression below rounded to the nearest hundredth? StartFraction 3.5 times 2 + 9 over 10.4 m
miskamm [114]

Answer:

The answer is 2.11~! I hope I helped <3

Step-by-step explanation:

3.5x2=7   7+9=16   1.4x2=2.8   10.4-2.8=7.6   16/7.6=2.10526315789

but we simplify so, 2.10526315789 rounded to the nearest hundredth is 2.11~!

 

7 0
2 years ago
Ashley plants a tree 45cm tall it grows by 10 cm each year. Find the amount ashley gets in the 5th year?​
Genrish500 [490]

Answer:

95cm

Step-by-step explanation:

45cm is the initial height

each year grow 10cm

growing time 5 years

45+(10 × 5)=95 cm

4 0
2 years ago
A closed cylindrical tank contains 36pi cubic feet of water and is filled to half its capacity. When the tank is placed upright
pentagon [3]

Answer:

2.12 ft above ground level

Step-by-step explanation:

Volume of the cylindrical tank is 36*π

Tank is filled to half its capacity, that means tank is filled 18*π, and level of water is 4 feet, then the height of the cylinder is 8 feet

With the above information we can calculate the radius of the base of the cylinder, according to

V  =  36*π  = π*r²*h     ⇒  36 = r²*h     ⇒   36/8 = r²    ⇒  r = 2.12 ft

Then the radius of the base is  2.12 ft

When the cylindrical tank is place on its side, the level of water inside have to be 2.12 ft above ground level. That is the level of half its capacity

7 0
2 years ago
Read 2 more answers
You and your friend each collect rocks and fossils. Your friend collects three times as many rocks and half as many fossils as y
pochemuha

Answer:

I collect 4 rocks and 16 fossils. While my friend collects 12 rocks and 8 fossils.

Step-by-step explanation:

The number of total objects collected by me  = 20

The number of objects collected by my friend  = 20

Let us assume:

The number of rocks collected by me  = m

The number of fossils collected by me  = 2 k

⇒ m +  2 k =  20  .... (1)

So, according to the question:

The number of rocks collected by my friend = 3 x (rocks collected by me)  

= 3 x (m)  = 3 m

The number of fossils collected by my friend = 1/2 x (fossils collected by me)    = 1/2 x (2k )  = k

⇒ 3 m +   k =  20  .... (2)

Solving (1)and (2) for the value of m and k, we get:

m +  2 k =  20     ⇒ m = 20 - 2 k ... Put this in (2)

3 m +   k =  20  ⇒  3 (20 - 2 k) +  k = 20

⇒ 60 - 6 k +  k  = 20

or, - 5k = -40

or, k = 40/5  = 8

⇒ k= 8

m + 2(8)  = 20

or, m = 4

Hence, the number of rocks collected by me  = m = 4

The number of fossils collected by me  =  2 k = 2 (4)  = 16

Hence, the number of rocks collected by my friend   = 3 m  = 3 x 4 = 12

The number of fossils collected by my friend   =   k =  8

Hence, I collect 4 rocks and 16 fossils. While my friend collects 12 rocks and 8 fossils.

4 0
2 years ago
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