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WINSTONCH [101]
2 years ago
8

Tim answered all the questions on his math test but got 101010 answers wrong. He received 444 points for every correct answer, a

nd there was no penalty for wrong answers. His score was 767676 points.
Write an equation to determine the total number of questions (q)(q)left parenthesis, q, right parenthesis on Tim's math test.
Mathematics
2 answers:
dolphi86 [110]2 years ago
7 0

Answer:

the equation would be 4(q-10)=76

and the amount of questions would be 29

Step-by-step explanation:

i did the test and i got this right! hope this was helpful!

3241004551 [841]2 years ago
6 0

Answer:

Step-by-step explanation:

Let x represent the number of questions that Tim got right in the math test.

The number of questions that Tim got wrong in the math test is 10.

If the total number of questions on the math test is q, it means that

x + 10 = q

If he received 4 points for every correct answer and there was no penalty for wrong answers, it means that he received 0 point for a wrong answer. If

his score was 76 points, it means that

4x + 0 × 10 = 76

4x = 76

Therefore, the required equations are

x + 10 = q

4x = 76

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Which table can be created using the equation below? –2 + 4x = y A 2-column table with 3 rows. Column 1 is labeled x with entrie
Pachacha [2.7K]

The correct answer is C. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 5, 0, 3. Column 2 is labeled y with entries negative 18, negative 2, 10.

Explanation:

The purpose of an equation is to show the equivalence between two mathematical expressions. This implies in the equation "–2 + 4x = y" the value of y should always be the same that -2 + 4x. Additionally, if a table is created with different values of x and y the equivalence should always be true. This occurs only in the third option.

   x                 y

   5                -18    

   0                -2

   3                 10

First row:

-2 + 4 (5) = y  (5 is the value of x which is first multyply by 4)

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Second row:

-2 + 4 (0) y

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Answer:

a. \frac{- 42,500}{(v + 60)(v - 40)}

Step-by-step Explanation:

Given:

Distance Ottawa to Québec = 425 km

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t = \frac{d}{r}

Required:

Flight times difference of the initial and return flights

Solution:

=>Flight time of the initial flight:

t = \frac{d}{r}

t = \frac{425}{v + 60}

=>Flight time of the return flight:

t = \frac{425}{v - 40}

=>Difference in flight times:

\frac{425}{v + 60} - \frac{425}{v - 40}

\frac{425(v - 40) -425(v + 60)}{(v + 60)(v - 40)}

\frac{425(v) - 425(40) -425(v) -425(+60)}{(v + 60)(v - 40)}

\frac{425v - 17000 -425v - 25500}{(v + 60)(v - 40)}

\frac{425v - 425v - 17000 - 25500}{(v + 60)(v - 40)}

\frac{- 42,500}{(v + 60)(v - 40)}

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