Two children are pulling and pushing a 30.0 kg sled. The child pulling the sled is exerting a force of 12.0 N at a 45o angle. Th
e child pushing the sled is exerting a horizontal a force of 8.00 N. There is a force of friction of 5.00 N. What is the acceleration of the sled? Round the answer to the nearest hundredth
2 answers:
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Answer:
Maximum emf = 5.32 V
Explanation:
Given that,
Number of turns, N = 10
Radius of loop, r = 3 cm = 0.03 m
It made 60 revolutions per second
Magnetic field, B = 0.5 T
We need to find maximum emf generated in the loop. It is based on the concept of Faraday's law. The induced emf is given by :
For maximum emf,
So,
So, the maximum emf generated in the loop is 5.32 V.