The answer is reverse faults.
Given :
Thin hoop with a mass of 5.0 kg rotates about a perpendicular axis through its center.
A force F is exerted tangentially to the hoop. If the hoop’s radius is 2.0 m and it is rotating with an angular acceleration of 2.5 rad/s².
To Find :
The magnitude of F.
Solution :
Torque on hoop is given by :
( Moment of Inertia of hoop is MR² )
Putting value of M, R and α in above equation, we get :

Therefore, the magnitude of force F is 25 N.
Hence, this is the required solution.
Answer:
1.056 x 10⁷ lb-ft
Explanation:
v = Speed of the bike = 20 mph
t = time of travel = 2 h
d = distance traveled by cyclist
Distance traveled by cyclist is given as
d = v t
d = (20) (2)
d = 40 miles
We know that, 1 mile = 5280 ft
d = 40 (5280) ft
d = 211200 ft
F = force applied by cyclist = 50 lb
W = work done by cyclist
Work done by cyclist is given as
W = F d
W = (50) (211200)
W = 1.056 x 10⁷ lb-ft
Answer:
(a) v = 15m/a
(b) No they won't feast because the rock can only rise to a height of 11.5m which is less than 15m.
Explanation:
Please see the attachment below for film solution.