a lady bug walks 10 cm forward then 5 cm backwards in 20 seconds. what is the average speed of the ladybug ?

Physics

1 answer:

igor_vitrenko [27]2 years ago

5 0

A lady bug moves 10 cm forward and 5 cm backwards

so total distance moved by lady bug = 10 + 5 = 15 cm

total time taken by the lady bug

t = 20 s

so the average speed is given as

$v = \frac{d}{t}$

$v = \frac{15}{20}$

$v = 0.75 cm/s$

so its average speed is 0.75 cm/s

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solution