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k0ka [10]
2 years ago
5

You are in a rocket moving away from Earth at one-third the speed of light relative to Earth. A friend is on Earth, and an astro

naut in another rocket is moving toward Earth at one-third the speed of light (in the Earth reference frame), on a path collinear with your path.
If each of you records the duration of your journey in your three respective reference frames, which of you records the proper time interval?

Check all that apply.

a. Your friend records your proper time interval.
b. The astronaut records your proper time interval.
c. You record your own proper time interval.
d. Nobody records your proper time interval.
Physics
1 answer:
Arisa [49]2 years ago
4 0

Answer:

i think C

Explanation:

You record your own proper time interval.

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A battery that produces a potential difference V is connected to a 10-W light bulb. Later, the 10-W bulb is replaced with a 20-W
uysha [10]

Answer:

The battery supply the greatest current with the 20-W bulb

Explanation:

The electrical power at a certain time by a two-terminal device is the product of the potential difference between the terminals and the current intensity that passes through the device. For this reason the power is proportional to the current and voltage. Mathematically can be written as:

P=VI

Let:

P_1=Electric\hspace{3}power\hspace{3}dissipated\hspace{3}by\hspace{3}the\hspace{3}10-W\hspace{3}bulb\\P_2=Electric\hspace{3}power\hspace{3}dissipated\hspace{3}by\hspace{3}the\hspace{3}20-W\hspace{3}bulb

The voltage remains constant for every case so:

I_1=Current\hspace{3}supply\hspace{3}by\hspace{3}the\hspace{3}battery\hspace{3}with\hspace{3}the\hspace{3}\hspace{3}10-W\hspace{3}bulb\\I_2=Current\hspace{3}supply\hspace{3}by\hspace{3}the\hspace{3}battery\hspace{3}with\hspace{3}the\hspace{3}\hspace{3}20-W\hspace{3}bulb

Then:

P_1=V*I_1=10W\\P_2=V*I_2=20W

Analyzing the equations it makes sense that the battery supplies the highest current with the 20 W bulb, because the power only depends on the voltage and the current, if the voltage remains constant, the only reason for the power to increase is due to current.

3 0
2 years ago
A student releases a block of mass m from rest at the top of a slide of height h1. The block moves down the slide and off the en
Nina [5.8K]

Answer:

B)   d = √  ( 4 h₂ ( H - 2h₂))

Explanation:

A) 1) If the height of the slide is very small, there is no speed to leave the table, therefore do not recreate almost any horizontal distance

2) If the height is very small downwards, it touches the earth a little and the horizon is small,

B) to find an equation for horizontal distance (d)

We must maximize the speed at the bottom of the slide let's use energy

Starting point Higher

         Em₀ = U = m g h₁

Final point. Lower (slide bottom)

           Emf = K + U = ½ m v² + m gh₂

As there is no friction the energy is conserved

            mgh₁ = ½ m v² + mgh₂

            v² = 2 g (h₁-h₂)

This is the speed with which the block leaves the table, bone is the horizontal speed (vₓ)

The distance traveled when leaving the table can be searched with kinematics, projectile launch

          x = v₀ₓ t

         y =  t - ½ g t²

The height is the height of the table (y = h₂), as it comes out horizontally the vertical speed is zero

        t = √ 2h₂ / g

We substitute in the other equation

        d = √ (2g (h₁-h₂))  √ 2h₂ / g

        d = √ (4 h₂ (h₁-h₂))

        H = h₁ + h₂

        h₁ = H -h₂

        d = √  ( 4 h₂ ( H - 2h₂))

Explanation:

7 0
2 years ago
Use Wien’s Law to calculate the peak wavelength of Betelgeuse, based on the temperature found in Question #8. Note: 1 nanometer
kodGreya [7K]

The peak wavelength of Betelgeuse is 828 nm

Explanation:

The relationship between surface temperature and peak wavelength of a star is given by Wien's displacement law:

\lambda=\frac{b}{T}

where

\lambda is the peak wavelength

T is the surface temperature

b=2.898\cdot 10^{-3} m\cdot K is Wien's constant

For Betelgeuse, the surface temperature is approximately

T = 3500 K

Therefore, its peak wavelength is:

\lambda=\frac{2.898\cdot 10^{-3}}{3500}=8.28\cdot 10^{-7} m = 828 nm

Learn more about wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

8 0
2 years ago
The Palo Verde nuclear power generator of Arizona has three reactors that have a combined generating capacity of 3.937×109 W . H
den301095 [7]

Answer:

t = 2.68 x 10¹⁴ years

Explanation:

First we need to find the amount of energy that Sun produce in one day.

Energy = Power * Time

Energy of Sun in 1 day = (3.839 x 10²⁶ W)(1 day)(24 hr/1 day)(3600 s/ 1 hr)

Energy of Sun in 1 day = 3.32 x 10³¹ J

Now, the time required by the nuclear power generator, in years, will be:

Energy of power generator = Energy Sun in 1 day = 3.32 x 10³¹ J

3.32 x 10³¹ J = Power * Time

3.32 x 10³¹ J = (3.937 x 10⁹ W)(t years)(365 days/1 year)(24 hr/1 day)(3600 s/ 1 hr)

t = 3.32 x 10³¹ /1.24 x 10¹⁷

<u>t = 2.68 x 10¹⁴ years</u>

8 0
2 years ago
You are on vacation in San Francisco and decide to take a cable car to see the city. A 5800-kgkg cable car goes 260 mm up a hill
Stella [2.4K]

Answer:

4.325\times10^6J

Explanation:

Mass of the cable car, m = 5800 kg

It goes 260 m up a hill, along a slope of \theta=17^o

Therefore vertical elevation of the car = 260sin\theta=260sin17^o=76.0166m

Now, when you get into the cable car, it's velocity is zero, that is, initial kinetic energy is zero (since K.E. = \frac{1}{2} mv^2). Similarly as the car reaches the top, it halts and hence final kinetic energy is zero.

Therefore the only possible change in the cable car system is the change in it's gravitational potential energy.

Hence, total change in energy = mgh = 5800\times9.81\times76.0166J=4.325\times10^6J

where, g = acceleration due to gravity

h = height/vertical elevation

4 0
2 years ago
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