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Harlamova29_29 [7]
2 years ago
11

In Section 5.6, we learned that triple bonds are stronger and shorter than single bonds. For example, a C- Csingle bond has an a

verage bond energy of 347 k.J/mole, while a C C triple bond has an average bond energy of 837 k.J/mole. Use valence bond theory to explain why a triple bond is not simply three times as strong as a single bond.
A) The C C triple bond is an exception. According to valence bond theory, a triple bond is generally three times as strong as a single bond. B) Because according to valence bond theory, a triple bond is the sharing of four electron pairs.
C) Because according to valence bond theory, a triple bond is actually composed of two different kinds of bonds, one σ and two π
Chemistry
1 answer:
Evgen [1.6K]2 years ago
3 0

Answer:

Because according to valence bond theory, a triple bond is actually composed of two different kinds of bonds, one σ and two π

Explanation:

The respective bond a energies of C-C single, double and triple bonds are; 347KJmol-1, 681 KJmol-1 and 837 KJmol-1 respectively.

It can be seen that the bond energy of a triple bond is really not thrice the bond energy of a C-C single bond. This is because, a triple bond is composed of two different kinds of bonds. A C-C sigma bond and two C-C pi bonds. The C-C sigma bonds are stronger than the C-C pi bonds because sigma bonds result from a greater degree of overlap between the atomic orbitals involved in the bond.

Hence, the C-C triple bond energy is not simply three times that of the C-C single bond energy since there are actually two different kinds of bonds present as explained above.

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weeeeeb [17]

Answer:

=> 572.83 K (299.83°C).

=> 95.86 m^2.

Explanation:

Parameters given are; Water flowing= 13.85 kg/s, temperature of water entering = 54.5°C and the temperature of water going out = 87.8°C, gas flow rate 54,430 kg/h(15.11 kg/s). Temperature of gas coming in = 427°C = 700K, specific heat capacity of hot gas and water = 1.005 kJ/ kg.K and 4.187 KJ/kg. K, overall heat transfer coefficient = Uo = 69.1 W/m^2.K.

Hence;

Mass of hot gas × specific heat capacity of hot gas × change in temperature = mass of water × specific heat capacity of water × change in temperature.

15.11 × 1.005(700K - x ) = 13.85 × 4.187(33.3).

If we solve for x, we will get the value of x to be;

x = 572.83 K (2.99.83°C).

x is the temperature of the exit gas that is 572.83 K(299.83°C).

(b). ∆T = 339.2 - 245.33/ln (339.2/245.33).

∆T = 93.87/ln 1.38.

∆T = 291.521K.

Heat transfer rate= 15.11 × 1.005 × 10^3 (700 - 572.83) = 1931146.394.

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Answer:

4.8 h

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