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2 years ago

How many grams of a solution that is 5.2% sucrose by mass are needed to obtain 18g of sucrose

Chemistry

1 answer:

kirill115 [55]2 years ago

3 0

Answer:

346.g of solution

Explanation:

In this case, if we have 5.2 % by mass it means that in 100 g of the solution we will have 5.2 g of glucose. Therefore we can do the calculation:

5.2 g of glucose = 100 g of solution

$18~g~of~glucose\frac{100~g~of~solution}{5.2~g~of~glucose}=346.15~g~of~solution$

So, if we need 8 g of glucose we had to have 346.15 g of solution

This logic can work for all types of solutions. By mass (as in this case), by volume or mass/volume.

I hope it helps!

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Which two scenarios illustrate the relationship between pressure and volume as described by Boyle’s law?

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The correct answer is option 2 and 3.

The two scenarios that illustrate the relationship between pressure and volume as described by Boyle’s law are as follows:

2. The volume of an underwater bubble increases as it rises and the pressure decreases.

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2 years ago

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A 2.0% (w/v) solution of sodium hydrogen citrate, Na2C6H6O7, which also contains 2.5% (w/v) of dextrose, C6H12O6, is used as an

tamaranim1 [39]

Answer:

0.0847M is molarity of sodium hydrogen citrate in the solution

Explanation:

The 2.0%(w/v) solution of sodium hydrogen citrate contains 2g of the solute in 100mL of solution. To find the molarity of the solution we need to convert the mass of solute to moles using molar mass and the mL of solution to Liters because molarity is the ratio between moles of sodium hydrogen citrate and liters of solution.

Moles Na2C6H6O7:

Molar Mass:

2Na: 2*22.99g/mol: 45.98g/mol

6C: 6*12.01g/mol: 72.01g/mol

6H: 6*1.008g/mol: 6.048g/mol

7O: 7*16g/mol: 112g/mol

45.98g/mol + 72.01g/mol + 6.048g/mol + 112g/mol = 236.038g/mol

Moles of 2g:

2g * (1mol / 236.038g) = 8.473x10⁻³ moles

Liters solution:

100mL * (1L / 1000mL) = 0.100L

Molarity:

8.473x10⁻³ moles / 0.100L =

<h3>0.0847M is molarity of sodium hydrogen citrate in the solution</h3>

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1 year ago

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2 years ago

Chlorine can bond with fluorine to form CIF. Chlorine can also bond with lithium to form LiCI Which compound will have a greater

Sergio [31]

Answer: $ClF$ will have a greater partial charge.

Explanation:

A polar covalent bond is defined as the bond which is formed when there is a low difference of electronegativities between the atoms, thus resulting in charge difference. Example: $ClF$

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