Molar mass <span>CH2BrCH2Br = 188.0 g/mol
1 mole ---------- 188.0 g
</span>0.500 moles ----- ?
mass = 0.500 * 188.0 / 1
= 94.0 g
Answer C
hope this helps!
Answer:
1) The bubbles will grow, and more may appear.
2)Can A will make a louder and stronger fizz than can B.
Explanation:
When you squeeze the sides of the bottle you increase the pressure pushing on the bubble, making it compress into a smaller space. This decrease in volume causes the bubble to increase in density. When the bubble increases in density, the bubble will grow and more bubbles will appear. Therefore, Changing the pressure (by squeezing the bottle) changes the volume of the bubbles. The number of bubbles doesn't change, just their size increases.
Carbonated drinks tend to lose their fizz at higher temperatures because the loss of carbon dioxide in liquids is increased as temperature is raised. This can be explained by the fact that when carbonated liquids are exposed to high temperatures, the solubility of gases in them is decreased. Hence the solubility of CO2 gas in can A at 32°C is less than the solubility of CO2 in can B at 8°C. Thus can A will tend to make a louder fizz more than can B.
The average speed is 0.28
Explanation:
When we are using spoon, beaker, stirring rod and graduated cylinder then they directly come in contact with the chemical we are using. Hence, if they are not washed thoroughly then chemicals remain deposited over them.
As a result, when successive test are performed using the same contaminated apparatuses then we do not get the desired results.
Whereas distilled water in a spray bottle if poured without touching or coming in contact with any kind of chemicals.
Hence, we can conclude that spoon, beaker, stirring rod and graduated cylinder are the tools that could have become cross-contaminated during the experiment if you had not cleaned them carefully between successive tests.
Molality (m) = moles of solute/ mass of solvent -(i)
moles of solute = 117.2 g/ 208.25 g mol∧-1 => 0.56 moles -(ii)
mass of solvent = density x volume (V) => 0.79 g/ml x V -(iii)
*putting values of m, (ii) & (iii) in (i)
0.75 = 0.56/0.79 V
0.56/(0.75 x 0.79) = V
V = 950 mL
