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2 years ago

How to give the spheres exactly equal but opposite charges?

Physics

1 answer:

Thepotemich [5.8K]2 years ago

4 0

Answer:

<em>B) Make sure spheres are not in contact with each other. Rub the glass rod on the silk to charge the rod positively (hence to charge piece of silk negatively). Touch one of the spheres with the glass rod then touch another one with the piece of silk.</em>

Explanation:

In static electricity, frictional rubbing can excite electrons, and make them jump from one material to another. Rubbing the glass rod and the silk together makes electron flow from the glass rod to the silk piece. On separation, the rod and silk will be seen to have equal amount of charge but, the glass rod will be positively charged from losing electron, and the silk piece will be negatively charged from gaining extra electrons. When they are each made to touch the metal spheres that are not in contact, the spheres will acquire equal amount of charges opposite the charge on the material that was used to charge them.

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Sunitha can type 1800 words in half an hour. What is her typing speed in words per minute?

Andre45 [30]

Answer:

60words/minute

Explanation:

If Sunitha can type 1800 words in half an hour, this can be expressed as;

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To get her typing speed per minute, we will use the formula

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1 year ago

as your roller coaster climbs to the top of the steepest hill on its track when does the first car have the greatest potential e

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2 years ago

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Dimas [21]

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2 years ago

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The headlights of a car emit light of wavelength 400 nm and are separated by 1.2 m. The headlights are viewed by an observer who

densk [106]

Answer:

The most correct option is;

B. 10 km

Explanation:

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Where:

y = Distance between the two headlights

d = Aperture of observers eye

λ = Wavelength of light

L = Distance between the observer and the headlight

Therefore, from the above solution, the distance between the observer and the headlights is 9386.066 km which is approximately 10 km.

Also we have

sinθ = y/L = 1.22 (λ/d)

$= 1.22 \times \frac{400 \times 10^{-9}}{0.004}$

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2 years ago

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A fish is 80 cm below the surface of a pond. What is the apparent depth (in cm) when viewed from a position almost directly abov

Rudik [331]

Answer:

Apparent depth (Da) = 60.15 cm (Approx)

Explanation:

Given:

Distance from fish (D) = 80 cm

Find:

Apparent depth (Da)

Computation:

We know that,

Refractive index of water (n2) = 1.33

So,

Apparent depth (Da) = D(n1/n2)

Apparent depth (Da) = 80 (1/1.33)

Apparent depth (Da) = 60.15 cm (Approx)

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2 years ago