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Oksanka [162]
2 years ago
8

Which graph represents a line with a slope of and a y-intercept equal to that of the line y = x – 2? A coordinate plane with a l

ine starting at (negative 2, negative 4), passing through (0, negative 2) and (2, 1). A coordinate plane with a line passing through (negative 3, 0) and (0, 2). A coordinate plane with a line passing through (0, 2) and (2, negative 1). A coordinate plane with a line passing through (negative 3, 0) and (0, negative 2).
Mathematics
2 answers:
Vera_Pavlovna [14]2 years ago
5 0

Answer:

(A)A coordinate plane with a line starting at (negative 2, negative 4), passing through (0, negative 2) and (2, 1).

Step-by-step explanation:

Given the line: y=x-2

Comparing with the slope-intercept form y=mx+b

  • Slope, m=1
  • y-intercept is -2.

Therefore, the point (0,-2) must be on the line.

Only Options A and D have this point.

We then determine which has a slope, m=1.

<u>Option A</u>

Using points (-2,-4) and (0,-2)

Slope, m=\dfrac{-2-(-4)}{0-(-2)} =\dfrac{-2+4}{2}=1

<u>Option D</u>

Using points (-3,0) and (0,-2)

Slope, m=\dfrac{-2-0}{0-(-3)} =-\dfrac{2}{3}

Therefore, Option A satisfy the requirements.

lys-0071 [83]2 years ago
3 0

Answer:

D

Step-by-step explanation:

The line would be negative and 2/3 is less than one so it decreases ver slowly. It is the bottom option below the 3, or D

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We need to calculate for the length of the model in ft.</span>

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length of the model = 1.148 ft

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<span>Going back to the calculation for the ratio,
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You work at a fruit market. Bananas cost 50¢ a pound. A customer hands you a bunch of bananas that weighs 3 pounds. How much sho
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Line GH contains points G(–2, 6) and H(5, –3). What is the slope of ?
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We will use the slope formula and fill it in accordingly.

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Answer:

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Translation of a figure about a vector \binom{-3}{1} means translation of a figure by 3 units to the left on x-axis and 1 unit in the positive direction of the y-axis.

Rule for the translation will be,

(x, y) → [(x - 3), (y + 1)]

From the figure attached,

Vertices of the triangle A are A(1, -1), B(1, -4) and C(3, -4)

After translation new image points will be A'(-2, 0), B'(-2, -3), C'(0, -3).

After rotation of these image points 180° about the origin will be,

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(x, y) → (-x, -y)

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8 0
2 years ago
6.In a sample of 131 women with cosmetic dermatitis from using eye shadow, 12 were diagnosed with a nickel allergy. In a sample
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Answer:

a) 0.0916 - 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.0422

0.0916 + 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.1410

So then we can conclude that the true proportion of women with cosmetic dermatitis from using eye shadow at 95% of confidence is between (0.0422 and 0.1410)

b) \hat p = \frac{25}{250}= 0.1

0.1 - 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.0628

0.1 + 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.1372

So then we can conclude that the true proportion of women with cosmetic dermatitis from using mascara at 95% of confidence is between (0.0628 and 0.1372)

c) For this case we see that both confidence intervals contains the value of 0.12 so then we can't conclude that only one group is referenced at the significance level of 0.05 used.

Step-by-step explanation:

Part a

The estimated proportion of women with cosmetic dermatitis from using eye shadow is given by:

\hat p =\frac{12}{131}= 0.0916

The confidence  interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the proportion is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

Replacing we got:

0.0916 - 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.0422

0.0916 + 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.1410

So then we can conclude that the true proportion of women with cosmetic dermatitis from using eye shadow at 95% of confidence is between (0.0422 and 0.1410)

Part b: A 95% confidence interval for the women with cosmetic dermatitis from using mascara

\hat p = \frac{25}{250}= 0.1

0.1 - 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.0628

0.1 + 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.1372

So then we can conclude that the true proportion of women with cosmetic dermatitis from using mascara at 95% of confidence is between (0.0628 and 0.1372)

Part c: Suppose you are informed that the true proportion with a nickel allergy for one of the two groups (eye shadow or mascara) is .12. Can you determine which group is referenced? Explain.

For this case we see that both confidence intervals contains the value of 0.12 so then we can't conclude that only one group is referenced at the significance level of 0.05 used.

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2 years ago
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