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Oksanka [162]
1 year ago
8

Which graph represents a line with a slope of and a y-intercept equal to that of the line y = x – 2? A coordinate plane with a l

ine starting at (negative 2, negative 4), passing through (0, negative 2) and (2, 1). A coordinate plane with a line passing through (negative 3, 0) and (0, 2). A coordinate plane with a line passing through (0, 2) and (2, negative 1). A coordinate plane with a line passing through (negative 3, 0) and (0, negative 2).
Mathematics
2 answers:
Vera_Pavlovna [14]1 year ago
5 0

Answer:

(A)A coordinate plane with a line starting at (negative 2, negative 4), passing through (0, negative 2) and (2, 1).

Step-by-step explanation:

Given the line: y=x-2

Comparing with the slope-intercept form y=mx+b

  • Slope, m=1
  • y-intercept is -2.

Therefore, the point (0,-2) must be on the line.

Only Options A and D have this point.

We then determine which has a slope, m=1.

<u>Option A</u>

Using points (-2,-4) and (0,-2)

Slope, m=\dfrac{-2-(-4)}{0-(-2)} =\dfrac{-2+4}{2}=1

<u>Option D</u>

Using points (-3,0) and (0,-2)

Slope, m=\dfrac{-2-0}{0-(-3)} =-\dfrac{2}{3}

Therefore, Option A satisfy the requirements.

lys-0071 [83]1 year ago
3 0

Answer:

D

Step-by-step explanation:

The line would be negative and 2/3 is less than one so it decreases ver slowly. It is the bottom option below the 3, or D

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Alexus [3.1K]

Answer:

The nth term of the sequence is

<h2>5 + 2n</h2>

Step-by-step explanation:

The sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

a = 7

d = 9 - 7 = 2 or 11 - 9 = 2

So the nth term for the sequence is

A(n) = 7 + ( n - 1)2

= 7 + 2n - 2

<h3>A(n) = 5 + 2n</h3>

Hope this helps you

5 0
1 year ago
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15 PINTS!!!!!!!!! PLZ HELP!!!!!!!! The linear function f(x) = 0.5x + 80 represents the average test score in your math class, wh
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Answer:

Part A: The test average for the math class after completing 2 tests is 81

Part B: The test average for the science class after completing 2 tests is 83

Part C: The science class had the higher average test score after completing the test 4.

Step-by-step explanation:

The average test score for math class is given by the linear function, f(x) = 0.5·x + 80

The data for the average test score for science g(x) are;

x,   q(x)

1,     81

2,    83

3,    85

Part A: The average test score for math after completing test 2 is given as follows;

f(2) = 0.5×2 + 80 = 81

∴ The test average for the math class after completing 2 tests = 81

Part B:

The average test score for science after completing test 2 is given from the table as at x = 2, g(2) = 83

∴ The test average for the science class after completing 2 tests = 83

Part C: After completing 4 tests, we have for the math class, f(4) = 0.5×4 + 80 = 82

For the science class, it is observed that common difference between each subsequent test score average is 2, therefore, the average test score, for the fourth test is 2 added to the average test score after the third test, which gives;

Average test score, after completing the fourth test for the science class, g(4) = 85 + 2 = 87

Since g(4) > f(4) the science class had the higher average test score after completing the test 4.

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Answer:

it should be $23

Step-by-step explanation:

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2 years ago
A special 8-sided die is marked with the numbers 1 to 8. It is rolled 20 times with these outcomes:
horsena [70]

Answer:

One: B

Two: 60% and 10%

Step-by-step explanation:

Problem One

There are only two numbers in the sample of 40 that are under 26. Both are 25. If you find more, make the adjustment. There are 2 more that are exactly 26 but they are not counted because the directions say "less than 26."

So set up your proportion

x/2000 = 2/40                     Multiply both sides by 2000

x = 2/40 * 2000

x = 4000/40

x = 100

A

I don't know where 5 comes from. But it is not correct.

B

B should be the correct answer.

C

Exactly 100 pieces should be defective. That is the theoretical result. C is incorrect.

D

D is not correct. The sample size would not be 40. It would have to be 2000 for D to be correct. So D is wrong.

E

We have enough data to get an answer. E is incorrect.

Problem 2

The think you must NOT do is count 1 as being prime. The prime numbers are 2 3 5 7 between 1 and 8. They break down as follows.

  • Prime           Number of them
  • 2                         3
  • 3                         4
  • 5                         2
  • 7                         3

The total number of primes = 12

There are 20 numbers in the sample

The experimental probability of tossing a prime is 12/20 * 100% = 60%

The non primes are 2 3 5 7 which is 4 out of 8

4/8 * 100 = 50%

The experimental value is 10% more than the theoretical value.

Discussion

Note: the problem may be one. This all depends on what you have been told about 1. I am using the exact wording of prime here. 1 is not a prime. It is also not a composite. So it has to be counted as part of the non primes.


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