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Rom4ik [11]
2 years ago
8

g Steel used for water pipelines is often coated on the inside with cement mortar to prevent corrosion. In a study of the mortar

coatings of the pipeline used in a water transmission project in California, researchers noted that the mortar thickness was specified to be 7/16 inch. A very large sample of thickness measurements produced a mean equal to 0.635 inch and astandard deviation equal to 0.082 inch. If the thickness measurements were normally distributed, approximately what proportion were less than 7/16 inch?
Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
7 0

Answer:

P(X

And we can find this probability using the z table and we got:

P(z

Step-by-step explanation:

Let X the random variable that represent the thickness of a population, and for this case we know the distribution for X is given by:

X \sim N(0.635,0.082)  

Where \mu=0.635 and \sigma=0.032

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the z table and we got:

P(z

You might be interested in
Gavin and Jim win some money and share it in the ratio 5:2. Gavin gets £39 more than Jim. How much did they get altogether?
gregori [183]

Answer:

Altogether Gavin and Jim won £95.

Step-by-step explanation:

We are given the following in the question:

Ratio of money won by Gavin and Jim = 5:2

Gavin gets £39 more than Jim.

Let x be the amount of money Won by Jim.

Then, money won by Gavin =

=(x+39)

Thus, we can write the equation:

\dfrac{\text{Gavin}}{\text{Jim}} = \dfrac{5}{2}=\dfrac{x+39}{x}

Solving, we get,

\dfrac{5}{2}=\dfrac{x+39}{x}\\\\5x = 2x + 78\\\Rightarrow 3x = 78\\\Rightarrow x = 26\\\Rightarrow (x+39) = 65

Thus, Gavin won £65 and Jim won £26.

Money won altogether =

=65 + 26\\=95

Thus, altogether Gavin and Jim won £95.

5 0
2 years ago
A truck stops at a gas station where diesel fuel costs $3.99 per gallon. The truck needs 8.8 gallons of diesel for the driver to
Dmitry [639]
36.00 will be enough to pay for fuel because if you multiply the 8.8 gallons of diesel needed by the fuel cost per gallon you get 35.112

6 0
2 years ago
Read 2 more answers
Change 21 out of 71 to a percentage. Give your answer to 1 decimal place
melisa1 [442]
1. 29.6%
2. 18.1%
3. 27.9%
4. 75.4%
3 0
2 years ago
Read 2 more answers
1. In a batch of 10 items, we wish to extract a sample of 3 without replacement. How many
svetlana [45]

Answer:

1) 120

2) E (Z) = 12 and Variance of Z = 90

a) 5 liters

Step-by-step explanation:

1. We can find this by suing combinations.

Here n= 10 and r= 3 so n C r

= 10 C 3= 120

2. E(X) = 8 and E(Y) = 3

Z = 2X - 3Y +5

E(Z ) = 2 E (X) - 3(E)(Y) +5   ( applying property for mean)

       = 2(8) - 3(3)+ 5 = 16+5-9= 21-9= 12

V(X) = 9 and V(Y) = 6.

V(Z) = E(Z )²-  V(X) *V(Y)   (applying property for Variance for two variables )

        = 144- 54= 90

3. 55 liters contain adulterated milk in 7: 4.

So it contains 4/ 11*55= 20 liters of water

But we want to make it a ratio of 7:6

the water will be 6/13 *55= 25.38 when rounded gives 25 liters of water

So 25- 20 = 5 liters must be added to make it a ratio of 7:6

6 0
2 years ago
.580 80 repeating as fraction
denis-greek [22]
First off, we'll move the non-repeating part in the decimal to the left-side, by doing a division by a power of 10.

then we'll equate the value to some variable, and move the repeating part over to the left as well.

anyhow, the idea being, we can just use that variable, say "x" for the repeating bit, let's proceed,

\bf 0.580\overline{80}\implies \boxed{\cfrac{5.80\overline{80}}{10}}\qquad \textit{now, let's say }x= 5.80\overline{80}\\\\
-------------------------------

\bf thus\qquad \begin{array}{llll}
100\cdot x&=&580.80\overline{80}\\
&&575+5.80\overline{80}\\
&&575+x
\end{array}\qquad \implies 100x=575+x
\\\\\\
99x=575\implies x=\cfrac{575}{99}\qquad therefore\qquad \boxed{\cfrac{5.80\overline{80}}{10}}\implies \cfrac{\quad \frac{575}{99}\quad }{10}
\\\\\\
\cfrac{\quad \frac{575}{99}\quad }{\frac{10}{1}}\implies \cfrac{575}{99}\cdot \cfrac{1}{10}\implies \cfrac{575}{990}\implies \stackrel{simplified}{\cfrac{115}{198}}

and you can check that in your calculator.
4 0
2 years ago
Read 2 more answers
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