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2 years ago

Nomenclatura: escribe la estructura lineo angular de los siguientes compuestos.

Chemistry

1 answer:

lilavasa [31]2 years ago

7 0

Answer:

Ver explicacion

Explanation:

a) 2,2,4-trimetilhexano

En esta molecula tenemos una cadena lineal de seis carbonos. En los carbonos 1,2 y 4 tenemos grupos metilos.

b) 3,6-dietil-2-metiloctano

Para esta molecula tenemos una cadena lineal de 8 carbonos. En el carbono dos tenemos un grupo metilo y en los carbonos tres y seis tenemos dos grupos etilo.

C) 3,5-dietil-2,8-dimetil-6-propilnonano

Finalmente, para esta molecula tenemos una cadena de nueve carbonos. En los carbonos dos y ocho tenemos 2 grupos metil, en los carbonos tres y cinco tenemos 2 grupos etilo y en el carbono seis tenemos un grupo propilo.

Ver figura 1

Espero sea de ayuda!

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Answer:

See explanation

Explanation:

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2 years ago

A piece of aluminum foil 1.00cm square and 0.590mm thick is allowed to react with bromine to form aluminum bromide. Part A How m

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Answer:

Part A: 5.899x10^-3 moles of Al

Part B: 1.573 g of AlBr3

Explanation:

Part A: We have to obtain the volume of the piece of aluminium; all sides of the square must be in cm. Then, use the density to obtain the mass.

$0.590 mm (\frac{1 cm}{10 mm}) = 0.059 cm$

$V= lxlxl= (1cm)(1cm)(0.059 cm)= 0.059 cm^3.$

0.059 is the volume of the Al udes for the reaction. Now, to oabtain the moles:

$0.059 cm^3 Al(\frac{2.699 g Al}{1 cm^3 Al})(\frac{1 mol Al}{27 g Al})= 5.899x10^-3 moles$

Part B: To obatin the mass of AlBr3, we need the balanced chemical equation:

2Al + 3Br2 → 2AlBr3

We assume bromine (Br2) is in excess, therefore, we calculate the aluminum bromide formed from the Al:

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2 years ago

2. If a machine produces 225 parts in an 8 hour day, how many minutes will it take to

vekshin1

21.28s

Explanation:

This is a rate problem.

Number of parts produced = 225

Time taken to produce= 8hours

Rate of production is the amount of parts produced in a duration of time.

Now convert 8 hours to minute;

60 minutes = 1hr

8 hours = 60 x 8 = 480minutes

Now:

Rate of production = $\frac{225 parts}{480min}$ = 0.47parts/minute

Now, to produce 10 parts;

It takes;

0.47 parts to be produced in 1 minute

10 parts would be produced in $\frac{10}{047}$ = 21.28s

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2 years ago

Write the expression for the equilibrium constant Kp for the following reaction.Enclose pressures in parentheses and do NOT writ

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Answer: The expression for $K_p$ is written below.

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