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PtichkaEL [24]
2 years ago
10

The Goliath six flags Magic Mountain roller coaster ride starts at 71.6 m (235 feet) above the ground. Assuming the coaster star

ts from rest and ignoring any friction, what is the speed of the coaster when it reaches the ground level
Physics
1 answer:
Sliva [168]2 years ago
8 0

Answer:

The  velocity is v  = 37 .46 \ m/s

Explanation:

From the question we are told that

    The start distance above the ground is  h  =  71.6 \ m

Generally according to the  law of energy conservation we have that

     PE_{top} =  KE_{bottom  }

Where PE_{top} is potential energy at the top which is mathematically represented as

      PE_{top} =  m * g * h

And  KE_{bottom } is the kinetic energy at the bottom which is mathematically represented as

     KE_{bottom } =  \frac{1}{2} * m *  v^2

Therefore  

       m * g  *  h  = \frac{1}{2}  *  m *  v^ 2

=>    v  = \sqrt{2 *  g * h  }

substituting value

     v  = \sqrt{2 *  9.8 * 71.6  }

     v  = 37 .46 \ m/s

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Answer:

210.3 degrees

Explanation:

The net force exerted on charge A = 59.5 N

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2 years ago
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A moving sidewalk 95 m in length carries passengers at a speed of 0.53 m/s. One passenger has a normal walking speed of 1.24 m/s
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Answer:

a) t = 1.8 x 10² s

b) t = 54 s

c) t = 49 s

Explanation:

a) The equation for the position of an object moving in a straight line at constan speed is:

x = x0 + v * t

where

x = position at time t

x0 = initial position

v = velocity

t = time

In this case, the origin of our reference system is at the begining of the sidewalk.

a) To calculate the time the passenger travels on the sidewalk without wlaking, we can use the equation for the position, using as speed the speed of the sidewalk:

x = x0 + v * t

95 m = 0m + 0. 53 m/s * t

t = 95 m/ 0.53 m/s

t = 1.8 x 10² s

b) Now, the speed of the passenger will be her walking speed plus the speed of th sidewalk (0.53 m/s + 1.24 m/s = 1.77 m/s)

t = 95 m/ 1.77 m/s = 54 s

c) In this case, the passenger is located 95 m from the begining of the sidewalk, then, x0 = 95 m and the final position will be x = 0. She walks in an opposite direction to the movement of the sidewalk, towards the origin of the system of reference ( the begining of the sidewalk). Then, her speed will be negative ( v = 0.53 m/s - 2*(1.24 m/s) = -1.95 m/s. Then:

0 m = 95 m -1.95 m/s * t

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3 0
2 years ago
A particular string resonates in four loops at a frequency of 320 Hz . Name at least three other (smaller) frequencies at which
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Answer:

160 Hz  ,  240 Hz  , 400 Hz

Explanation:

Given that

Frequency of forth harmonic is 320 Hz.

Lets take fundamental frequency = f₁

f_1=\dfrac{320}{4}\ Hz

f₁=80 Hz

Frequency of first harmonic = f₂

f₂=2 f₁

f₂ =2 x 80 = 160 Hz

Frequency of second harmonic = f₃

f₃= 3 f₁=3 x 80 = 240 Hz

Frequency of fifth harmonic = f₅

f₅=  5 f₁= 5 x 80 = 400 Hz

Three frequencies are as follows

160 Hz  ,  240 Hz  , 400 Hz

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Answer:

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This question can be solved with this simple formula:

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8 0
2 years ago
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