answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dimulka [17.4K]
2 years ago
6

The molecular mass of propane-1,2-diol is 76.1 amuamu . Calculate the molecular mass of propane-1,3-diol, an isomer of propane-1

,2-diol
Chemistry
2 answers:
sashaice [31]2 years ago
8 0

Answer:

76.1 amu

Explanation:

Let us recall that isomers refer to two different compounds with the same molecular formula but different atom to atom connectivity and different chemical properties. When two compounds are isomers, we can essentially represent them with exactly the same molecular formula.

Now propane-1,2-diol and propane-1,3-diol are both represented by the molecular formula C3H8O2 since they are isomers of each other. When two compounds have the same molecular formula, they must essentially have the same molecular mass. Hence the molecular mass of propane-1,3-diol is also 76.1 amu.

galben [10]2 years ago
4 0

Answer:

molecular mass of propane-1,3-diol, an isomer of propane-1,2-diol = 76.1 amu

Explanation:

An isomer of any compound will also have the same molecular mass of the comlund

You might be interested in
A student is setting up a model to study the carbon cycle and natural sources of carbon dioxide. They create a microenvironment
cluponka [151]

Fossil fuels, forest fires, and respiration and major metabolic process photosynthesis are left out of the model.                

<u>Explanation</u>:

  • The carbon cycle model contains all the activities but some points are missing in it. Oceans, the burning of fossil fuels should be explained.  Natural elements such as coal and natural gas are the main elements of the carbon cycle.
  • Because they are important compounds of the carbon cycle. The process of photosynthesis is very important in the carbon cycle. The process of volcanic eruption should be explained in the carbon cycle.        

4 0
2 years ago
A race car is driven by a professional driver at 99 . What is this speed in and ? 1 mile = 1.61 kilometers 1 hour = 60 minutes E
slavikrds [6]

Answer: The speed is equivalent to <u>159.39 kilometers per hour </u>or <u>2.65 kilometers per minute.</u>

Explanation:

Given, The speed of a race car = 99 miles/ hour

To convert the speed into  kilometers per hour and kilometers per minute

Since   1 mile = 1.61 kilometers

So, Speed of car = (99 ) x (1.61 )

= 159.39 kilometers per hour.

Also, 1 hour = 60 minutes

Then, Speed of car = (159.39) ÷60

= 2.6565≈2.65 kilometer per minute.

Hence, the speed is equivalent to <u>159.39 kilometers per hour </u>or <u>2.65 kilometers per minute.</u>

4 0
2 years ago
Explain what happens to an ionic substance when it dissolves in water. Drag the terms on the left to the appropriate blanks on t
nignag [31]

Answer:

false

Explanation:

5 0
2 years ago
A 100. mL sample of 0.200 M aqueous hydrochloric acid is added to 100. mL of 0.200 M aqueous ammonia in a calorimeter whose heat
Free_Kalibri [48]

Answer:

-154KJ/mol

Explanation:

mole of 100ml sample of 0.2M aqueous HCl = Molarity × volume in Liter

= 0.2 × 100 / 1000  ( 1L = 1000 ml) = 0.02 mol and 0.02 mole of HCl solution require 0.02 mole of ammonia according to the mole ratio in the balanced equation.

Heat loss by the reaction = heat gain by calorimeter = mcΔT + 480 J/K

where m is the mass of water = 100g + 100g = 200g since mass of 100ml of water = 100g and it is in both of them and specific heat capacity of water 4.184 J/gK

heat gain by calorimeter  = (4.184 × 200 + 480) × 2.34 = 3081.3 J

ΔH per mole = heat loss / number of mole = 3081.3 / 0.02 = 154065.6 = -154KJ/mol

8 0
2 years ago
Using the following thermochemical equation, determine the amount of heat produced from the combustion of 24.3 g benzene (C6H6).
Anna007 [38]

Answer:

ΔH = -976.5 kJ

Explanation:

For the reaction given, there are 2 moles of benzene (C6H6). The heat of this reaction is -6278 kJ, which means that the combustion of 2 moles of benzene will lose 6278 kJ of heat. It is an exothermic reaction.

The value of ΔH, the enthalpy, is a way of measurement of the heat, and it depends on the quantity of the matter (number of moles).

So, 24.3 g of benzene has :

n = mass/ molar mass

n = 24.3/78.11

n = 0.311 moles

2 moles ------------ -6278 kJ

0.311 moles ----------- x

By a simple direct three rule:

2x = -1953.08

x = -976.5 kJ

3 0
2 years ago
Other questions:
  • In the chemical reaction NaHCO3 + CH3COOH → CH3COONa + H2O +CO2, 83 g of sodium bicarbonate reacts with 70 g of acetic acid. Whi
    5·1 answer
  • What crossed-aldol product results when butanal is heated in the presence of excess benzaldehyde and sodium hydroxide? draw the
    10·1 answer
  • The vapor pressure of Substance X is measured at several temperatures:temperature (C) vapor pressure (atm)34 0.23644 0.29254 0.3
    13·1 answer
  • The solubility of CaCl2 in water is 25g per 50 mL of H2O. How many grams of CaCl2 will dissolved to form a saturated solution in
    7·1 answer
  • if 5.50 mol of calcium carbide (CaC 2 ) reacts with an excess of water, how many moles of acetylene (C 2 H 2 ) , a gas used in w
    12·1 answer
  • 7.47 Two atoms have the electron configurations 1s22s22p6 and 1s22s22p63s1. The first ionization energy of one is 2080 kJ/mol an
    6·1 answer
  • What element has the electron configuration 1s^22s^22p^63s^23s^23p^4? ​
    10·1 answer
  • A 0.500 g sample of tin (Sn) is reacted with oxygen to give 0.534 g of product. What is the empirical formula of the oxide?
    12·1 answer
  • See the reference image for the chemical equation for the reaction you just observed. What do you think each side of the equatio
    6·1 answer
  • calculate the ph of one solution containing 0.1 M formic acid and 0.1 M sodium formate before and after the addition of 1mL of 5
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!