Answer: This chemical reaction is a neutralization reaction between the Milk of Magnesia and the HCl from the stomach. The balanced equation is Mg(OH)2 (s) + 2 HCl (aq) → MgCl2 (aq) + 2 H2O (l)
Explanation:
The reaction between the HCl and the Mg(OH)2 is a neutralizacion reaction , because the HCl is a strong acid and the Mg(OH)2 is a weak base, then both react and the pH of the medium will increase, so the stomach trouble will dissapear.
Mg(OH)2 (s) + 2 HCl (aq) → MgCl2 (aq) + 2 H2O (l)
Magnesium hydroxide is a weak base due to its very limited solubility in water. This property is a great advantage when treating the excess of HCl in the stomach, because the Mg(OH)2 molecule does not dissociated easily until it reacts with the hydrogen ion, H+ of the HCl. So the effect of the Mg(OH)2 will last longer until the annoyance dissapear.
Hello!
The statement that a solution of sodium acetate (CH₃COONa) is weakly basic is true:
Sodium acetate is the conjugate base of Acetic Acid. When sodium acetate is dissolved in water, it follows the equation that is shown below:
CH₃COONa(s) → CH₃COO⁻(aq) + Na⁺(aq)
Now the Acetate (CH₃COO⁻) ion, has an equilibrium in water to produce hydroxyl (OH⁻) ions and (Acetic Acid CH₃COOH)
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻
This is a weak equilibrium, and the hydroxyl ions cause the solution to be weakly basic.
Have a nice day!
<span>A 50-gram sample with a half-life of 12 days will have a remaining mass of 25 grams after its 12-day half-life.
Every cycle of a half-life, the sample will lose half of its mass, so if the half-life, itself, is 12 days and the time period passing is 12 days, one half-life has passed and the material will be halved.</span>
Answer:
4.16L
Explanation:
From the question given, we obtained the following data:
Molarity = 0.225 M
Number of mole of KI = 0.935mole
Volume =?
Molarity = mole / Volume
Volume = mole /Molarity
Volume = 0.935/0.225
Volume = 4.16L
Therefore, 4.16L of KI is needed.
In this question, you are given the NaOH volume but asked for concentration.
Don't forget that for every 1 mol of NaOH there will be 1 mol OH- ion, but for every 1 mol of H2SO4 there will be 2 mol of H- ion.
To neutralize you need the same amount of OH- and H+, so the equation should be:
OH-= H+
<span>35.50cm3 * x*1= 25cm3* 0.2mol/dm3 *2
</span>x= 10/35.5 mol/dm3= 0.2816/dm3
