Answer: the answer is C
Step-by-step explanation:
Answer:
$393.50+/-$19.72
= ( $373.78, $413.22)
Therefore, the 95% confidence interval (a,b) = ($373.78, $413.22)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = $393.50
Standard deviation r = $50.30
Number of samples n = 25
Confidence interval = 95%
z value(at 95% confidence) = 1.96
Substituting the values we have;
$393.50+/-1.96($50.30/√25)
$393.50+/-1.96($10.06)
$393.50+/-$19.7176
$393.50+/-$19.72
= ( $373.78, $413.22)
Therefore, the 95% confidence interval (a,b) = ($373.78, $413.22)
Angle BAC = (180 - 114) degrees = 66 degrees [angle on a straight line]
Angle OCA = Angle OBA = 90 degrees [angle at the point where the tangent and the radius meet]
Thus, the measure of arc BC = (360 - 66 - 90 - 90) degrees = 114 degrees [sum of interior angles of a quadrilateral]
Angle CDE = (180 - 124) degrees = 56 degrees [angle on a straight line]
Angle OCD = Angle OED = 90 degrees [angle at the point where the tangent and the radius meet]
Thus, the measure of arc CE = (360 - 56 - 90 - 90) degrees = 124 degrees [sum of interior angles of a quadrilateral]
Given that the measure of arc BC is 114 degrees and the measure of arc CE is 124 degrees, thus the measure of arc BE = (360 - 114 - 124) degrees = 122 degrees [angle at a point]
Angle OBF = Angle OEF = 90 degrees [angle at the point where the tangent and the radius meet]
Thus, angle BFE = (360 - 122 - 90 - 90) degrees = 58 degrees.
Answer:
Since you didn't provide any choices, a possible equations would be h = (m - 10) / 5
Step-by-step Solution:
Since we know that the flat-rate 10 doesn't have anything to do with the hourly rate, we first subtract that. Then, we divide that number by 5 to get rid of it, so we're only left with h.
This process of removing things from the equation by reversing their methods can be applied all over math and is a strategy vary commonly used.
