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IRINA_888 [86]
2 years ago
11

If the patient has to be administered a dosage of 2 tablets every 8 hours for 7 days, what is the number of tablets required for

the prescribed dosage?
Chemistry
1 answer:
Lilit [14]2 years ago
6 0
If the patient has to take 2 tablets every 8 hours for 7 days.
 24/8=3     3*2=6
this means that he patient will have to take 6 tablets every day. 
6*7=42   And the patient must take 42 tablets in all 7 days
Hope this helps! :)
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Hydrogen sulfide (H2S) is a common and troublesome pollutant in industrial wastewaters. One way to remove H2S is to treat the wa
Kryger [21]

Explanation:

As the given reaction is as follows.

     H_{2}S(aq) + Cl_{2}(aq) \rightarrow S(s) + 2H^{+}(aq) + 2Cl^{-}(aq)

So, according to the balanced equation, it can be seen that rate of formation of Cl^{-} will be twice the rate of disappearance of H_{2}S .

And, it is known that rate of disappearance of reactant will be negative and rate of formation of products will be positive value.

This means that,

Rate of the reaction = -Rate of disappearance of H_{2}S

                 = k[H_{2}S][Cl_{2}]

                 = (3.5 \times 10^{-2}) \times (2 \times 10^{-4}) \times (2.8 x 10^{-2})

                 = 1.96 \times 10^{-7} M/s

Therefore, calculate the rate of formation of Cl^{-} as follows.

Rate of formation of Cl^{-} = 2 \times 1.96 \times 10^{-7}

                                        = 3.92 \times 10^{-7} M/s

Thus, we can conclude that the rate of formation of Cl^{-} is 3.92 \times 10^{-7} M/s.

5 0
2 years ago
Determine the chemical formula for the compound, diaquadicarbonylzinc tetrabromopalladate(iv).
kati45 [8]
Missing question:
<span>A. [PdZn(H2O)2(CO)2]Br4. 
B. [Zn(H2O)2(CO)2]2[PdBr4]. 
C. [Pd(H2O)2][Zn(CO)2]Br4. 
D. [Pd(H2O)2]2[Zn(CO)2]3Br4. 
E. [Zn(H2O)2(CO)2][PdBr4].
</span>Answer is: E. [Zn(H2O)2(CO)2][PdBr4]..
In this complex diaqua means two waters (H₂O), <span>dicarbonyl means two carbonyl groups (CO), zinc(Zn) and palladium (Pd) are central atoms or metals, bromine has negative charge -1. Bromine, water and carbonyl are ligands.</span>
6 0
2 years ago
Read 2 more answers
In a polar reaction mechanism, the atom that gives away electrons in a neutral nucleophile will end up as a(n):
Ray Of Light [21]

The question is incomplete, the complete question is shown in the image attached.

Answer:

Cation

Explanation:

In a polar reaction mechanism, a specie must give out electrons and another specie must accept those electrons.

The specie that gives out electrons becomes electron deficient and positively charged so we refer to such a specie as a cation.

Hence, the specie that looses electrons becomes a cation.

5 0
2 years ago
An iron(iii) sulfate hydrate is 18.4% water. What is the formula of the hydrate? What is the name of the hydrate?
aleksley [76]

Answer:- Formula of the hydrate is Fe_2(SO_4)_3.5H_2O and it's name is Iron(III)sulfate pentahydrate.

Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.

Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.

We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:

81.6gFe_2(SO_4)_3(\frac{1mol}{399.88g})

= 0.204molFe_2(SO_4)_3

18.4gH_2O(\frac{1mol}{18.02g})

= 1.02molH_2O

Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.

Fe_2(SO_4)_3=\frac{0.204}{0.204}  = 1

H_2O=\frac{1.02}{0.204} = 5

There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is Fe_2(SO_4)_3.5H_2O and the name of the hydrate is Iron(III)sulfate pentahydrate.


3 0
2 years ago
2N2H4(l) + N2O4(l) → 3N2(g) + 4H2O(g) [balanced] How many moles of N2H4 is required to produce 28.3 g of N2? Assume that all rea
JulijaS [17]

Answer: 0.67 moles of N_2H_4

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles of nitrogen}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{28.3}{28.02}=1mole

2N_2H_4(l)+N_2O_4(l)\rightarrow 3N_2(g)+4H_2O(g)

According to stoichiometry:

3 moles of N_2 is produced by 2 moles of N_2H_4

Thus 1 mole of N_2 is produced by= \frac{2}{3}\times 1=0.67moles of N_2H_4

Thus 0.67 moles of N_2H_4 are required to produce 28.3 g of N_2

6 0
2 years ago
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