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beks73 [17]
2 years ago
6

The complex ion Fe(CN)63- is paramagnetic with one unpaired electron. The complex ion Fe(SCN)63- has five unpaired electrons. Wh

ere does SCN- lie in the spectrochemical series with respect to CN-?
Chemistry
1 answer:
charle [14.2K]2 years ago
7 0

Answer:

SCN- is a weak field ligand while CN- is a strong field ligand

Explanation:

The spectrochemical series is an arrangement of ligands according to their magnitude of crystal field splitting. Ligands that cause only a small degree of crystal field splitting are called weak field ligands while ligands that cause large crystal field splitting are called strong field ligands.

Strong field ligands often lead to the formation of low spin complexes with the least number of unpaired electrons while high spin complexes are formed by weak field ligands.

CN- is a strong field ligand as it lies towards the right hand side of the spectrochemical series.

SCN- is a weak field ligand hence it forms a high spin complex having the maximum number of unpaired electrons for Fe^3+, hence the answer.

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Consider the balanced equation below. 4NH3 + 3O2 --&gt; 2N2 + 6H2O What is the mole ratio of NH3 to N2?
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The balanced equation given is:
4NH3 + 3O2 .....> 2N2 + 6H2O

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What is the mass of 3.35 mol Hg(IO3)2? 1,700 g 1,840 g 1,960 g 2,110 g
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Answer:- 1840 g.

Solution:- We have been given with 3.35 moles of Hg(IO_3)_2 and asked to calculate it's mass.

To convert the moles to grams we multiply the moles by the molar mass of the compound. Molar mass of the compound is the sum of atomic masses of all the atoms present in it.

molar mass of Hg(IO_3)_2 = atomic mass of Hg + 2(atomic mass of I) + 6(atomic mass of O)

= 200.59+2(126.90)+6(16.00)

= 200.59+253.80+96.00

= 550.39 gram per mol

Let's multiply the given moles by the molar mass:

3.35mol(\frac{550.39g}{1mol})

= 1843.8 g

Since, there are three sig figs in the given moles of compound, we need to round the calculated my to three sig figs also. So, on rounding off to three sig figs the mass becomes 1840 g.

8 0
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A gas has a pressure of 3.16 atm at STP. I have decided to transfer it to a container that is 3 times larger than the original v
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Answer: The new pressure will be 1.1atm

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P2 = (3.16 x V) /3V

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7 0
2 years ago
Hydrogen sulfide (H2S) is a common and troublesome pollutant in industrial wastewaters. One way to remove H2S is to treat the wa
Kryger [21]

Explanation:

As the given reaction is as follows.

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So, according to the balanced equation, it can be seen that rate of formation of Cl^{-} will be twice the rate of disappearance of H_{2}S .

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This means that,

Rate of the reaction = -Rate of disappearance of H_{2}S

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Rate of formation of Cl^{-} = 2 \times 1.96 \times 10^{-7}

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Thus, we can conclude that the rate of formation of Cl^{-} is 3.92 \times 10^{-7} M/s.

5 0
2 years ago
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