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o-na [289]
2 years ago
9

A farmer was asked how many cows and chickens she has. The farmer replied, "between the cows and the chickens, there are 162 eye

s and 270 feet." How many cows does she have? How many chickens does she have? (Note: chickens have 2 feet and cows have 4 feet.)
Mathematics
1 answer:
Kazeer [188]2 years ago
8 0
<h2>☀️ <u>Solution</u><u>:</u></h2>

We all know that,

  • All animals have 2 eyes.
  • All cows have 4 feet
  • All hens have 2 feet

So, Let the no. of cows be x and chickens be y

According to question,

  • Total number of eyes = 162

Framing equation,

⇛ Eyes of cows + Eyes of chickens = 162

⇛ 2x + 2y = 162

⇛ 2(x + y) = 162

⇛ x + y = 162/2 = 81 -----------(1)

According to question(Cond.-1)

  • Total number of feet = 270

Framing equation,

⇛ Feet of cows + Feet of chickens = 270

⇛ 4x + 2y = 270

⇛ 2(2x + y) = 270

⇛ 2x + y = 135 ----------(2)

Subtracting eq.(1) from eq.(2),

⇛ 2x + y - (x + y) = 135 - 81

⇛ 2x + y - x - y = 54

⇛ x = 54

Putting value of x in eq.(1),

⇛ 54 + y = 81

⇛ y = 81 - 54

⇛ y = 27

⚘ So, Total number of animals,

  • Number of cows = x = 54
  • Number of chickens = y = 27

Hence, solved !!

<u>━━━━━━━━━━━━━━━━━━━━</u>

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A city determines that a planned community must have at least 4 acres of developed and open space, and the difference
FinnZ [79.3K]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x ----->  the number of open acres

y ---->  the number of developed acres

we know that

x+y \geq 4 -----> inequality A

x\leq 1 ----> inequality B

Remember that

if the number of open acres, x, can be no more than 1. then the number of open acres, x must be less than or equal to 1

Solve the system of equations by graphing

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The graph in the attached figure

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2 years ago
Helppp please.
Sati [7]
The solution
m = s + 5 
<span>m - 4 = (3s) - 3 </span>
<span>(s + 5) - 4 = 3s - 3 </span>
<span>s + 1 = 3s - 3 </span>
<span>s = 3s - 4 </span>
<span>-2s = -4 </span>
<span>s = 2 </span>
<span>m = 7 </span>
<span>Check this: </span>

<span>m - 4 = 3s - 3 </span>
<span>7 - 4 = 3(2) - 3 </span>
<span>3 = 6 - 3 </span>
<span>3 = 3 </span>

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A standard weight known to weigh 10 grams. Some suspect bias in weights due to manufacturing process. To assess the accuracy of
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Answer:

a) The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams

b) 49 measurements are needed.

Step-by-step explanation:

Question a:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.01 = 0.99, so Z = 2.327.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.327\frac{0.0003}{\sqrt{5}} = 0.00031

The lower end of the interval is the sample mean subtracted by M. So it is 10.0044 - 0.00031 = 10.00409 grams

The upper end of the interval is the sample mean added to M. So it is 10 + 0.00031 = 10.00471 grams

The 98% confidence interval for the mean weight is between 10.00409 grams and 10.00471 grams.

(b) How many measurements must be averaged to get a margin of error of +/- 0.0001 with 98% confidence?

We have to find n for which M = 0.0001. So

M = z\frac{\sigma}{\sqrt{n}}

0.0001 = 2.327\frac{0.0003}{\sqrt{n}}

0.0001\sqrt{n} = 2.327*0.0003

\sqrt{n} = \frac{2.327*0.0003}{0.0001}

(\sqrt{n})^2 = (\frac{2.327*0.0003}{0.0001})^2

n = 48.73

Rounding up

49 measurements are needed.

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lina2011 [118]

Answer:

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Step-by-step explanation:              

we know that            

The equation of the line into point slope form is equal to                        

y-y1=m(x-x1)              

In this problem we have          

(x_1,y_1)=(4,\frac{1}{3})                            

m=\frac{3}{4}            

substitute the given values                

y-\frac{1}{3}=\frac{3}{4}(x-4)

therefore

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