Greek engineers had the unenviable task of moving large columns from the quarries to the city. One engineer, Chersiphron, tried
several different techniques to do this. One method was to cut pivot holes into the ends of the stone and then use oxen to pull the column. The 4-ft diameter column weighs 13200 lbs, and the team of oxen generates a constant pull force of 1500 lbs on the center of the cylinder G. Knowing that the column starts from rest and rolls without slipping, determine the velocity of its center G after it has moved 5 ft and the minimum static coefficient of friction that will keep it from slipping.
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Answer:
F = - 50 N
Hence, the magnitude of resultant force is 50 N and its direction is leftwards.
Explanation:
The magnitude of the resultant force is always equal to the sum of all forces. While, the direction of resultant force will be equal to the direction of the force with greater magnitude:
considering right direction to be positive:
F₁ = Force applied on right rope = 150 N
F₂ = Force applied on left rope = 200 N
Therefore, the resultant force can be found by using these values in equation:
<u>F = - 50 N</u>
<u>Hence, the magnitude of resultant force is 50 N and its direction is leftwards.</u>
We know the equation of motion v = u+ at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
In this case Final velocity = -3.1 m/s, negative sign indicates it is pointing downward.
acceleration = - 3.7m/ . Negative means acceleration is towards center of planet Mars.
Time taken = 3 seconds
So jumping velocity of Julia = 8 m/s