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Vera_Pavlovna [14]
2 years ago
7

Portland cement concrete (PCC) has a density of 150 lb/ft3. How many kilograms of PCC are required to cast a cylindrical column

1.15 m in diameter and 7.8 m in height? (1 kg = 2.205 lb, 1 inch = 2.54 cm)
Chemistry
1 answer:
Ksivusya [100]2 years ago
5 0

Answer:

Mass, m = 19466.7 kg

Explanation:

Given that,

Portland cement concrete (PCC) has a density of 150 lb/ft³

We need to find how many kilograms of PCC are required to cast a cylindrical column 1.15 m in diameter and 7.8 m in height.

Since, 1 kg = 2.205 lb

1 lb/ft³ = 16.018 kg/m³

150 lb/ft³ = 2402.77 kg/m³

Density, d=\dfrac{m}{V}

m is mass of PCC in kg and V is volume of cylinder

m=d\times V

m=d\times \pi r^2 h\\\\m=2402.77\times \pi \times (1.15/2)^2\times 7.8\\\\m=19466.70\ kg

So, the mass of PCC required is 19466.7 kg.

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Answer:

Pb^2+(aq) + 2F-(aq) → PbF2(s)

Explanation:

Step 1: Data given

sodium fluoride = NaF

lead(II)nitrate Pb(NO3)2

Step 2: The unbalanced equation

NaF(aq) + Pb(NO3)2(aq) →  PbF2(s) + NaNO3(aq)

Step 3: Balancing the equation

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On the left side we have 2x NO3 (in Pb(NO3)2), on the right side we have 1x NO3 (in NaNO3). To balance the amount of NO3 we hvae to multiply NaNO3 on the right side by 2.

NaF(aq) + Pb(NO3)2(aq) →  PbF2(s) + 2NaNO3(aq)

On the left side we have 1x Na (in NaF), on the right side we have 2x Na (in 2NaNO3). To balance the amount of Na we have to multiply NaF on the left side by 2. Now the equation is balanced.

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Step 4: Calculate net ionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side, look like this:

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2 years ago
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Answer:

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