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Inessa [10]
2 years ago
6

How would you know if this combination is likely to be found in some dirt?

Chemistry
1 answer:
Mkey [24]2 years ago
6 0

Answer:

  very unlikely to be found in dirt

Explanation:

That combination has a ratio of ¹⁴N to ¹⁵N of 10:4 = 2.5: 1. The most ¹⁵N enriched natural material has a ratio of ¹⁴N to ¹⁵N on the order of 250 : 1 or higher. The combination shown is very unlikely to be found in dirt.

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Calculate the mass in grams of each of the following amounts: 1.002 mol of chromium 4.08 x 10-8 mol of neon
Pepsi [2]

Answer:

Mass_{chromium}=52.1\ g

Mass_{neon}=8.23\times 10^{-7}\ g

Explanation:

<u>Calculation of the mass of chromium as:- </u>

Moles = 1.002 moles

Molar mass of chromium = 51.9961 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

1.002\ mol= \frac{Mass}{51.9961\ g/mol}

Mass_{chromium}=1.002\times 51.9961\ g = 52.1\ g

<u>Calculation of the mass of neon as:- </u>

Moles = 4.08\times 10^{-8} moles

Molar mass of neon = 20.1797 g/mol

Thus,

1.002\ mol= \frac{Mass}{20.1797\ g/mol}

Mass_{neon}=4.08\times 10^{-8}\times 20.1797\ g = 8.23\times 10^{-7}\ g

6 0
2 years ago
A 103.8g sample of nitric acid solution that is 70.0% HNO3 contains by mass
soldi70 [24.7K]
w/w percentage <span>
               = mass of the pure compound / total mass of the sample x 100%

70% HNO₃ contains by mass means every 100 g of sample has 70 g of HNO₃.</span><span>

The mass of solution = 103.8 g
Hence the mass of HNO₃ = 103.8 g x 70%</span><span>
                                         = 103.8 g x (70 / 100)
<span>                                         = 72.66 g = 72.7 g.</span></span>
3 0
2 years ago
Which of the following trends is indirectly proportional to effective nuclear charge, Zeff
Julli [10]

Answer : Option C) Atomic Size

Explanation : The atomic radius of the elements is found to be decreasing if we go from left to right in the modern periodic table. Accordingly, Z_{eff} increases as the number of shielding electrons present in the atomic nucleus of the periodic elements which lies in the same row remains constant while the number of protons in each atomic shell increases.

The effective nuclear charge Z_{eff} of an atom is defined as the net positive charge which is felt by the valence electron of the atomic element.

When Z_{eff} is observed to decrease, it is seen that the atomic radius grows in size. So, it explains the inverse relationship between both. This phenomenon occurs, because there is more screening of the electrons from the nucleus taking place, which is observed due to decrease the attraction between the electron and the nucleus.

7 0
2 years ago
Read 2 more answers
Several amino acids are intermediates of the urea cycle, having side ammonia groups that join with free carbon dioxide (CO2) and
mr_godi [17]

Answer:

A. Arginine

Explanation:

The urea cycle is the cycle of the biochemical reactions which produces urea from ammonia.

Steps of the urea cycle:

  • Carbamoyl phosphate, in presence of ornithine transcarbamoylase is converted to citrulline by the denotation of carbamoyl phosphate groupto ornithine and a phosphate group is released.
  • Amino group of the aspartate and carbonyl group of the citrulline are condensed to form argininosuccinate in the presence of enzyme, argininosuccinate synthetase. This condensation reaction is ATP dependent.
  • <u>Argininosuccinate then undergoes cleavage by the argininosuccinase to form intermediate, arginine and fumarate.</u>
  • <u>Arginine is then cleaved by the arginase to form urea as well as ornithine.</u> Ornithine is transported back to mitochondria to begin urea cycle again.
7 0
2 years ago
Calculate the radius ratio for NaBr if the ionic radii of Na + and Br − are 102 pm and 196 pm , respectively. radius ratio: Base
Fudgin [204]

Answer : The expected coordination number of NaBr is, 6.

Explanation :

Cation-anion radius ratio : It is defined as the ratio of the ionic radius of the cation to the ionic radius of the anion in a cation-anion compound.

This is represented by,

\frac{r_{cation}}{r_{anion}}

When the radius ratio is greater than 0.155, then the compound will be stable.

Now we have to determine the radius ration for NaBr.

Given:

Radius of cation, Na^+ = 102 pm

Radius of cation, Br^- = 196 pm

\frac{r_{cation}}{r_{anion}}=\frac{102}{196}=0.520

As per question, the radius of cation-anion ratio is between 0.414-0.732. So, the coordination number of NaBr will be, 6.

The relation between radius ratio and coordination number are shown below.

Therefore, the expected coordination number of NaBr is, 6.

8 0
2 years ago
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