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Savatey [412]
2 years ago
15

How many moles are equal to 89.23 g of calcium oxide?

Chemistry
2 answers:
adelina 88 [10]2 years ago
0 0
The molecular formula of calcium oxide - CaO
The molar mass of CaO - 40 + 16 = 56 g/mol 
Which means that 1 mol weighs 56 g
Therefore 56 g of CaO is - 1 mol
Then 89.23 g is equivalent to - 1/56 x 89.23 = 1.6 mol of CaO
erica [24]2 years ago
0 0

Answer : 1.593 moles are equal to 89.23 g of calcium oxide.

Solution : Given,

Mass of calcium oxide = 89.23 g

Molar mass of calcium oxide = 56 g/mole

Formula used :

\text{Moles of }CaO=\frac{\text{Mass of }CaO}}{\text{Molar mass of }CaO}

Now put all the given values in this formula, we get the moles of calcium oxide.

\text{Moles of }CaO=\frac{89.23g}{56g/mole}=1.593moles

Therefore, 1.593 moles are equal to 89.23 g of calcium oxide.

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Use average bond energies to calculate ΔHrxn for the following hydrogenation reaction: H2C=CH2(g)+H2(g)→H3C−CH3(g)
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Answer:

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Explanation:

The given chemical reaction is as follows.

H_{2}C=CH_{2}(g)+H_{2}(g)\rightarrow H_{3}C-CH_{3}(g)

Enthalpy of each reactant and products are as follows.

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In the given chemical reaction involved two C-H bonds in the reactant side and one C-C bond in the product side therefore, the enthalpy of formation will be the negative.

\Delta H_{rxn}=-\Delta H_{C-C}-2\Delta H_{C-H}+\Delta H_{C=C}+\Delta H_{H-H}

=-347.4-2\times416.2+615.0+435.1

=-129.6 \,kJ

Therefore, The\Delta H_{rxn} of the given reaction is -129.6 kJ

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