Answer:
1. pOH = 2.4
2. pOH = 10.34
3. pH = 2.14
Explanation:
1. Determination of the pOH.
Concentration of Hydroxide ion, [OH-] = 0.004 M
pOH =?
pOH = - log [OH-]
pOH = - log (0.004)
pOH = 2.4
Therefore, the pOH of the solution is 2.4
2. Determination of the pOH.
pH = 3.66
pOH =?
pH and pOH are related by the following equation:
pH + pOH = 14
With the above formula, we can obtain the pOH of the solution as follow:
pH = 3.66
pOH =?
pH + pOH = 14
3.66 + pOH = 14
Collect like terms
pOH = 14 - 3.66
pOH = 10.34
Therefore, the pOH of the solution is 10.34
3. Determination of the pH.
Molarity of HCl = 0.0072 M
Concentration of Hydrogen ion, [H+] =?
Thus, we can obtain the concentration of Hydrogen ion, [H+] as follow:
HCl(aq) —> H+(aq) + Cl-(aq)
From the balanced equation above,
1 mole of HCl produced 1 mole of H+.
Therefore, 0.0072 M HCl will also produce 0.0072 M H+.
Therefore, the concentration of Hydrogen ion, [H+] in the solution is 0.0072 M.
Finally, we shall determine the pH of the solution as follow:
Concentration of Hydrogen ion, [H+] = 0.0072 M.
pH =?
pH = - log [H+]
pH = - log (0.0072)
pH = 2.14
Therefore, the pH of the solution is 2.14
= 59 capsules