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Sergio039 [100]
2 years ago
6

Dua buah gaya masing-masing F1 = 10 N dan F2 = 5 N bekerja pada sebuah benda yang:

Chemistry
1 answer:
Stolb23 [73]2 years ago
6 0

Pertanyaan ini tidak ditulis dengan benar.

Pertanyaan Lengkap:

Duah buah gaya masing masing F1=10N dan F2=5N bekerja pada sebuah benda yang terletak pada suatu permukaan lantai. Jika benda berpindah ke kanan sejauh 5 meter,usaha yang dilakukan pada benda oleh kedua gaya tersebut adalah

Answer:

75 Nm or 75 Joules

Explanation:

Dari pertanyaan tersebut, kami telah diberikan parameter berikut:

F1 = 10N

F2 = 5N

D = 5 Meter.

Kita diminta untuk mencari atau menghitung usaha yang dilakukan pada benda oleh dua gaya.

Rumus kerja yang dilakukan pada suatu benda dengan dua gaya =

W = (F1 + F2) × D

Dimana D = Perpindahan benda

W = (10N + 5N) × 5m

W = 15N × 5m

W = 75Nm atau 75Joules

Oleh karena itu, usaha yang dilakukan pada benda tersebut dengan dua gaya = 75Nm atau 75 Joules

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