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weqwewe [10]
2 years ago
9

PLZ HELP ASAP PLATO!!! BRAINLIEST TO WHOEVER ANSWERS CORRECTLY!!!

Chemistry
1 answer:
katen-ka-za [31]2 years ago
3 0

Explanation:

a. 0.0093

Number of significant figures = 2

All zero’s preceding the first integers are never significant

b. 120.9

Number of significant figures = 4

All zero’s between integers are always significant.

c. 1,000

Number of significant figures = 1

All zeroes used solely for spacing the decimal point are not significant.

d. 1.008

Number of significant figures = 4

All zero’s between integers are always significant.

All zero’s after the decimal point are always significant.

e. 670

Number of significant figures = 2

All zeroes used solely for spacing the decimal point are not significant.

f. 0.184

Number of significant figures = 3

All zero’s after the decimal point are always significant.

g. 1.30

Number of significant figures = 3

All zero’s after the decimal point are always significant.

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A 36 gram sample of water has an initial temperature of 22 degrees Celsius after the sample absorbs 1200joules of heat energy th
UkoKoshka [18]

<span>We can use the heat equation,
Q = mcΔT </span>

 

<span>Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g</span>⁻¹ °C⁻<span>¹) and ΔT is the temperature difference (°C).</span>


Let's assume that the finale temperature is T.

Q = 1200 J

<span> m = 36 g
c = 4.186 J/g °C</span>

ΔT = (T - 22) 

 

By applying the formula,

   1200 J = 36 g x 4.186 J/g °C x (T - 22)

  (T - 22) = 1200 J / (36 g x 4.186 J/g °C)

  (T - 22) = 7.96 °C

            T = (7.96 + 22) °C = 29.96 °C

            T = 30 °C 


Hence, the final temperature is 30 °C.

8 0
2 years ago
Read 2 more answers
A chemist has 2.0 mol of methanol (CH3OH). The molar mass of methanol is 32.0 g/mol. What is the mass, in grams, of the sample?
rodikova [14]

Answer:

\boxed {\boxed {\sf D. \ 64 \ grams }}

Explanation:

Given the moles, we are asked to find the mass of a sample.

We know that the molar mass of methanol is 32.0 grams per mole. We can use this number as a fraction or ratio.

\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}

Multiply by the given number of moles, which is 2.0

2.0 \ mol \ CH_3OH *\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}

The moles of methanol will cancel each other out.

2.0 \ *\frac{32 \ g \ CH_3OH}{1 }

The denominator of 1 can be ignored.

2.0 * 32 \ g\ CH_3OH

Multiply.

64 \ g \ CH_3OH

There are 64 grams of methanol in the sample.

3 0
1 year ago
Which will not appear in the equilibrium constant expression for the reaction below?
n200080 [17]

Answer:

[C] carbon solid

Explanation:

Pure solids and liquids are never included in the equilibrium constant expression because they do not affect the reactant amount at equilibrium in the reaction, thus since your equation has [C] as solid it will not be part of the equlibrium equation.

5 0
2 years ago
Consider the following oxides: SO2, Y2O3, MgO, Cl2O, and N2O5. How many are expected to form acidic solutions in water? Consider
Snowcat [4.5K]

Answer:

Three of the five oxides are expected to form acidic solutions in water

Explanation:

We have different types of oxides : Acidic oxides, Basic oxides, Amphoteric oxides, Peroxides and Higher oxides.

Only acidic oxides will dissolve in water to give an acidic solution.

Considering the given oxides carefully,

  • SO2 will dissolve in water to produce H2SO3 which is acidic.

  • Y2O3 will dissolve in water to produce Yttrium(III) hydroxide which is basic.

  • MgO will dissolve in water only to produce Mg(OH)2 which is also basic.

  • Cl2O dichlorine mono oxide will dissolve in water to produce HClO which is acidic.

  • N2O5 will dissolve in water to produce HNO3 which is also acidic.

5 0
1 year ago
A 2 mole sample of F2(g) reacts with excess NaOH(aq) according to the equation above. If the reaction is repeated with excess Na
77julia77 [94]

Answer:

The amount of NaF produced is doubled.

(d) is correct option.

Explanation:

Given that,

A 2 mole sample of F₂ reacts with excess NaOH according to the equation.

The balance equation is

2F_{2}+2NaOH\Rightarrow 2NaF +H_{2}O+OF_{2}

If the reaction is repeated with excess NaOH but with 1 mole of F₂

The balance equation is

F_{2}+2NaOH\Rightarrow 2NaF +2OH

Hence, The amount of NaF produced is doubled.

(d) is correct option.

6 0
1 year ago
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