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weqwewe [10]
2 years ago
9

PLZ HELP ASAP PLATO!!! BRAINLIEST TO WHOEVER ANSWERS CORRECTLY!!!

Chemistry
1 answer:
katen-ka-za [31]2 years ago
3 0

Explanation:

a. 0.0093

Number of significant figures = 2

All zero’s preceding the first integers are never significant

b. 120.9

Number of significant figures = 4

All zero’s between integers are always significant.

c. 1,000

Number of significant figures = 1

All zeroes used solely for spacing the decimal point are not significant.

d. 1.008

Number of significant figures = 4

All zero’s between integers are always significant.

All zero’s after the decimal point are always significant.

e. 670

Number of significant figures = 2

All zeroes used solely for spacing the decimal point are not significant.

f. 0.184

Number of significant figures = 3

All zero’s after the decimal point are always significant.

g. 1.30

Number of significant figures = 3

All zero’s after the decimal point are always significant.

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I would say that Candace's answer is d. wide-ranging. she didn't get the exact / precise (they mean the same thing) answer.

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natulia [17]

Answer:

The partial pressure of NO2  = 0.152 atm

Explanation:

Step 1: Data given

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Total pressure at equilibrium = 0.674 atm

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Step 3: The initial pressure

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0.500 + x = 0.674 atm

x = 0.174 atm

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Answer:

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2 years ago
If fluorine 20 undergoes beta decay , what will it become ?
e-lub [12.9K]
Fluorine 20 (F - Atomic number 9 and atomic mass 20). Firstly we need to know what is beta decay. Beta decay occurs when one neutron changes into a proton and an electron therefore the atomic mass will remain the same as even though we loose a neutron it is replaced by a proton, the atomic number is always raised by 1 when one beta decay occurs. The produced electron is shot out of the nucleus at an incredible speed. This speedy electron we call a beta particle.

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Sodium azide decomposes rapidly to produce nitrogen gas. 2 nan3(s) → 2 na(s) + 3 n2(g) what mass of sodium azide will inflate a
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We solve for n of N₂ gas from the ideal gas equation:

PV=nRT
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Through stoichiometric calculations,
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