Question

1 liter is equivalent to a volume of 1000 cm3 (the same as 10 cm x 10 cm x 10 cm). If a beaker has a cross-section the size of the circle below, and a height of 10 cm, what is its volume

Answer 1

Answer:

$Volume = \frac{220}{7}r^2$

Step-by-step explanation:

Given

Height = 10cm

See Attachment for complete question

Required

Determine the volume of the circle

The volume is calculated as thus;

$Volume = \pi r^2h$

Take $\pi$ as $\frac{22}{7}$

So; Volume becomes

$Volume = \frac{22}{7} * r^2 * h$

Substitute 10 for h

$Volume = \frac{22}{7} * r^2 * 10$

$Volume = \frac{220}{7} * r^2$

Since, the value of the radius is not given;

The volume of the circle is:

$Volume = \frac{220}{7}r^2$