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masha68 [24]
2 years ago
9

The total sound power, in decibels, from x objects each producing 50 decibels of sound power is given by the function f(x) = 50

+ 10 log x. Suppose each of the x objects increases its sound power by 10 decibels, so that the new total sound power, in decibels, is given by the function g(x) = f(x) +10
which shows the graphs of f(x) and g(x)?

Mathematics
1 answer:
pashok25 [27]2 years ago
6 0

Answer:

the answer is A

Step-by-step explanation:

edgenuity

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Round 645 to the nearest ten
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645 rounded to the nearest 10 is 650, as 5 in the ones place rounds up.
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2 years ago
A case in riverhead, new york, nine different crime victims listened to voice recordings of five different men. all nine victims
Alexus [3.1K]

the complete question in the attached figure

1) Find the probability that all nine victims would select the same person. You should enter your answer as a decimal, not as a percent. Do not round, as your answer should be a terminating decimal.

P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512

2) what is the probability that the first victim picks SOMEONE? ANYONE? 

P=(1/5)=0.20  ---------------- > 20%

3) Now let’s look at victim #2. What is the probability that they pick the same person as victim #1?

P=(1/5)*(1/5)=0.04 --------------> 4%

4) Now let’s look at victim #3. What is the probability that they pick the same person as victim #1?

P=(1/5)*(1/5)*(1/5)=0.008 --------------> 0.8%

5) Now let's look at victim #9. What is the probability that they pick the same person as victim #1? 

P=(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)*(1/5)=0.000000512

6) Once you find all those probabilities, what rule would apply?

the probability is given by (1/5)^n

n=number of victims that pick the same person---------> in this problem = 9

P=(1/5)^9= 0.000000512

5 0
2 years ago
In two or more complete sentences, describe the transformation(s) that take place on the parent function, f(x) = log(x), to achi
lubasha [3.4K]

Answer:

Shift 2 unit left

Flip the graph about y-axis

Stretch horizontally by factor 2

Shift vertically up by 2 units

Step-by-step explanation:

Given:

Parent function: f(x)=\log x

Transformation function: f(x)=\log(-2x-4)+2

Take -2 common from transform function f(x)

f(x)=\log[-2(x+2)]+2

Now we see the step-by-step translation

f(x)=\log x

Shift 2 unit left ( x → x+2 )

f(x)=\log(x+2)

Flip the graph about y-axis ( (x+2)  → - (x+2) )

f(x)=\log[-(x+2)]

Stretch horizontally by factor 2 [ -x(x+2) → -2(x+2) ]

f(x)=\log[-2(x+2)]

Shift vertically up by 2 units [ f(x) → f(x) + 2 ]

f(x)=\log[-2(x+2)]+2

Simplify the function:

f(x)=\log(-2x-4)+2

Hence, Using four step of transformation to get new function f(x)=\log(-2x-4)+2

3 0
2 years ago
Read 2 more answers
A charity receives 2025 contributions. Contributions are assumed to be mutually independent and identically distributed with mea
uysha [10]

Answer:

The 90th percentile for the distribution of the total contributions is $6,342,525.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums of size n, the mean is \mu*n and the standard deviation is s = \sqrt{n}*\sigma

In this question:

n = 2025, \mu = 3125*2025 = 6328125, \sigma = \sqrt{2025}*250 = 11250

The 90th percentile for the distribution of the total contributions

This is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. Then

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

1.28 = \frac{X - 6328125}{11250}

X - 6328125 = 1.28*11250

X = 6342525

The 90th percentile for the distribution of the total contributions is $6,342,525.

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2 years ago
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mina [271]
So far she scored 11 out of 15, which is a chance of 11/15, which is also the experimental probability for her next throw.
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2 years ago
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