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Ksenya-84 [330]
2 years ago
15

A standard backpack is approximately 30cm x 30cm x 40cm. Suppose you find a hoard of pure gold while treasure hunting in the wil

derness. How much mass would your backpack hold if you filled it with the gold? An average student has a mass of 70 kg. How do these values compare?
Chemistry
1 answer:
Blizzard [7]2 years ago
8 0

Explanation:

The dimensions of a standard backpack is 30cm x 30cm x 40cm

The mass of an average student is 70 kg

We know that, the density of gold is 19.3 g/cm³.

Let m be the mass of the backpack. So,

\text{density}=\dfrac{\text{mass}}{\text{volume}}\\\\m=d\times V\\\\m=19.3\ g/cm^3\times (30\times 30\times 40)\ cm^3\\\\m=694800\ g\\\\\text{or}\\\\m=694.8\ kg\approx 700\ kg

An average student has a mass of 70 kg. If we compare the mass of student and mass of backpack, we find that the backpack is 10 times of the mass of the student.

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A waste collection tank can hold 18754 kg of methanol, which has a density of 0.788 g/cm3.
quester [9]
Given:
Mass of methanol, m = 18754 kg
Density of methanol, ρ = 0.788 g/cm³

By definition, the volume of methanol in the collection tank is
Volume  = mass/density
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Answer:  2.38 x 10⁷ g/cm³
3 0
2 years ago
How much volume (in cm3) is gained by a person who gains 11.1 lbs of pure fat?
kirill [66]

The density of human fat is 0.918 g/cm^{3}. The mass of the pure fat is 11.1 lbs.

First convert mass from lb to g as follows:

1 lb=453.592 g

Thus,

11.1 lb\rightarrow 11.1\times 453.592 g=5034.875 g

Density of a substance is defined as mass per unit volume, thus volume can be calculated as:

V=\frac{m}{d}

Putting the values,

V=\frac{5034.875 g}{0.918 g/cm^{3}}=5484.61 cm^{3}

Therefore, volume gained by person will be 5484.61 cm^{3}.

6 0
2 years ago
How many grams of (nh4)3po4 are needed to make 0.250 l of 0.150 m (nh4)3po4? hints how many grams of (nh4)3po4 are needed to mak
NeX [460]
<span>There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. We calculate the mass of the solute by first determining the number of moles needed. And by using the molar mass, we can convert it to units of mass.

Moles </span>(nh4)3po4 = 0.250 L (0.150 M) = 0.0375 moles (nh4)3po4
Mass = 0.0375 mol (nh4)3po4 (149.0867 g / mol) = 5.59 g (nh4)3po4
5 0
2 years ago
3. What is the atomic mass of phosphorous if phosphorous-29 has a percent abundance of 35.5%, phosphorous-30 has a percent abund
daser333 [38]

Answer:

The atomic mass of phosphorus is 29.864 amu.

Explanation:

Given data:

Atomic mass of phosphorus = ?

Percent abundance of P-29 = 35.5%

percent abundance of P-30 = 42.6%

Percent abundance of P-31 = 21.9%

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass  / 100

Average atomic mass  = (29×35.5)+(30×42.6) + (31×21.9) /100

Average atomic mass =  1029.5 + 1278 + 678.9/ 100

Average atomic mass  = 2986.4 / 100

Average atomic mass = 29.864 amu.

The atomic mass of phosphorus is 29.864 amu.

5 0
2 years ago
Which equations shows the complete dissociation of a strong base?
galben [10]
The correct answer is the fourth option. The complete dissociation of a strong base is BOH + h20 -> B+ + OH- + H20 since this is the only base from the choices given. A base is a substance that accepts hydrogen ions. 
3 0
2 years ago
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