Answer:
One Angle = 110°
Other Angle = 70°
Step-by-step explanation:
A linear pair means that two angles are in a straight line (or, a straight angle).
A straight line is 180 degrees.
THey are supplementary.
We can say one angle is "a" and another one is "b".
<em>One angle is 10 MORE THAN 2/3rds of the other, we can write:</em>
<em>
</em>
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<em>Also, since they are supplementary (add up to 180), we can write:</em>
<em>a + b = 180</em>
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We can now substitute 1st equation in this one and find b:

Since a + b = 180, we can write:
a + 110 = 180
so,
a = 180 - 110
a = 70
Thus,
One Angle = 110°
Other Angle = 70°
Answer:
The second option
Step-by-step explanation:
The given system of equation is
x+2y=3
-x+y+z=2
y-2z=-3
The augment matrix is obtained by combining the coefficient matrix with the constant matrix to obtain;
![\left[\begin{array}{cccc}1&2&0&|3\\-1&1&1&|2\\0&1&-2&|-3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%262%260%26%7C3%5C%5C-1%261%261%26%7C2%5C%5C0%261%26-2%26%7C-3%5Cend%7Barray%7D%5Cright%5D)
Note that the absence of z, in the first equation means its coefficient is zero. The same thing applies to x in the last equation.
The correct choice is the second option.
The potential energy, E, of the penny is given by E=mgh. The energy, Q, required to raise the temperature of an object by an amount ΔT is given by Q=mcΔT. We can equate these two to get the result but we must use proper units and include the 60%:
(0.6)mgh=mcΔT
We see we can divide out the mass from each side
0.6gh=cΔT, then 0.6gh/c=ΔT
(0.6)9.81(m/s²)50m/385(J/kg°C) = 0.7644°C
since this is the change in temperature and it started at 25°C we get
T=25.7644°C
As you can see the result does not depend on mass. The more massive the copper object the more potential energy it will have to contribute to the heat energy, but the more stuff there will be to heat up, and the effect is that the mass cancels.