In scientific notation 674.3mm equals

) a charge of 6.15 mc is placed at each corner of a square 0.100 m on a side. determine the magnitude and direction of the force

Nana76 [90]

Because charges are positioned on a square the force acting on one charge is the same as the force acting on all others.
We will use superposition principle. This means that force acting on the charge is the sum of individual forces. I have attached the sketch that you should take a look at.
We will break down forces on their x and y components:
$F_x=F_3+F_2cos(45^{\circ})$
$F_y=F_1+F_2sin(45^{\circ})$
Let's figure out each component:
$F_1=\frac{1}{4\pi \epsilon}\frac{q^2}{a^2}\\
F_3=\frac{1}{4\pi \epsilon}\frac{q^2}{a^2}\\$
$F_2=\frac{1}{4\pi \epsilon}\frac{q^2}{(\sqrt{2}a)^2}$
Total force acting on the charge would be:
$F=\sqrt{F_x^2+F_y^2}$
We need to calculate forces along x and y axis first( I will assume you meant micro coulombs, because otherwise we get forces that are huge).
$F_x=F_3+F_2cos(45^{\circ})=\frac{1}{4\pi \epsilon}\frac{q^2}{a^2}+\frac{1} {4\pi \epsilon}\frac{q^2}{(\sqrt{2}a)^2}\cdot\cos(45)=46N$
$F_y=\frac{1}{4\pi \epsilon}\frac{q^2}{(\sqrt{2}a)^2}\cdot sin(45)+\frac{1}{4\pi \epsilon}\frac{q^2}{a^2}=46N$
Now we can find the total force acting on a single charge:
$F=\sqrt{F_x^2+F_y^2}=\sqrt{46^2+46^2}=65N$
As said before, intensity of the force acting on charges is the same for all of them.

5 0

2 years ago

The process of generating electricity from dams and nuclear power plants is very different, but some of the energy transformatio

storchak [24]

There are only two correct options. Kinetic energy to mechanical energy, and mechanical energy to electrical energy.

8 0

2 years ago

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When the tube is filled with mercury vapor, as in this case, a sharp drop in the collected current is observed when the accelera

Phantasy [73]

Answer:

253.54 nm

Explanation:

h = Planck's constant = $6.626\times 10^{-34}\ m^2kg/s$

c = Speed of light = $3\times 10^8\ m/s$

$\lambda$ = Wavelength

V = Voltage = 4.9 V

The loss in kinetic energy = Gain in potential energy (energy conservation)

$E=eV\\\Rightarrow E=1.6\times 10^{-19}\times 4.9\\\Rightarrow E=7.84\times 10^{-19}\ J$

Energy is given by

$E=\dfrac{hc}{\lambda}\\\Rightarrow \lambda=\dfrac{hc}{E}\\\Rightarrow \lambda=\dfrac{6.626\times 10^{-34}\times 3\times 10^{8}}{7.84\times 10^{-19}}\\\Rightarrow \lambda=2.53546\times 10^{-7}=253.54\ nm$

The wavelength is 253.54 nm

8 0

2 years ago

A solution is oversaturated with solute. which could be done to decrease the oversaturation?

Grace [21]

<span>A solution is oversaturated with solute. The thing that could be done to decrease the oversaturation is to add more solvent in order to decrease the concentration of the solute. You can also increase the temperature to increase solubility of the solute. Hope this answers the question.</span>

4 0

2 years ago

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A boat with a weight of 547 newtons is floating in a harbor. What is the buoyant force on the boat?

Veronika [31]

Answer:

a

Explanation:

its correct

3 0

2 years ago