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Ivan
2 years ago
5

Here's an interesting challenge you can give to a friend. Hold a $1 (or larger!) bill by an upper corner. Have a friend prepare

to pinch a lower corner, putting her fingers near but not touching the bill. Tell her to try to catch the bill when you drop it by simply closing her fingers. This seems like it should be easy, but it's not. After she sees that you have released the bill, it will take her about 0.25 s to react and close her fingers - which is not fast enough to catch the bill.
How much time does it take for the bill to fall beyond her grasp? The length of a bill is 16 cm.
Physics
1 answer:
Brrunno [24]2 years ago
8 0

Answer:

t <t _reaction

We see from this that the bill passes completely through the fingers before the reaction time (time without movement) passes and therefore before closing the fingers.

Explanation:

In this exercise we can use the free fall kinematics, let's calculate the time that the upper corner of the bill takes to pass through the fingers of her friend, when releasing the bill it starts with zero speed, let's use the equation

         y = v₀ t + ½ g t²

         y = ½ g t²

         t = √(2y / g)

let's calculate

         t = √ (2 0.16 / 9.8)

         t = 0.18 s

the reaction time is

         t_reaction = 0.25 s

Thus

         t <t _reaction

We see from this that the bill passes completely through the fingers before the reaction time (time without movement) passes and therefore before closing the fingers.

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Answer:

2014.44 N

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\frac{g'}{g}=\left (\frac{R}{r}  \right )^{2}

\frac{g'}{g}=\left (\frac{R}{3R}  \right )^{2}

g' = g / 9

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F = m g' = 1850 x 1.089

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A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,00
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A 1.0 kg object moving at 4.5 m/s has a wavelength of:
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By wave particle  duality.

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Answer:

The net torque is 0.0372 N m.

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\frac{\omega^{2}-\omega_{0}^{2}}{2\Delta\theta}=\alpha

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with ∑τ the net torque and I the moment of inertia of the sphere, for a sphere that rotates about an axle through its center its moment of inertia is:

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