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Ad libitum [116K]
2 years ago
5

Which set contains no ionic species?

Chemistry
1 answer:
SVEN [57.7K]2 years ago
7 0
The awnser should be A
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The weight percent of concentrated HClO4(aq) is 70.5% and its density is 1.67 g/mL. What is the molarity of concentrated HClO4
ollegr [7]

Answer:

[HClO₄] = 11.7M

Explanation:

First of all we need to know, that a weight percent represents, the mass of solute in 100 g of solution.

Let's convert the mass to moles → 70.5 g . 1mol/100.45 g = 0.702 moles

Now we can apply the density to calculate the volume.

Density always refers to solution → Solution density = Solution mass / Solution volume

1.67 g/mL = 100 g / Solution volume

Solution volume = 100 g / 1.67 g/mL → 59.8 mL

To determine molarity (mol/L) we must convert the mL to L

59.8 mL . 1L/1000mL = 0.0598 L

Molarity → Moles of solute in 1L of solution → 0.702 mol / 0.0598 L = 11.7M

8 0
2 years ago
A student measured the mass of some sodium chloride for a lab. the lab called for 6.25 g (the accurate measurement ) , but the s
Yuri [45]

Answer:

The answer is

\huge 4\%

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual mass = 6.25 g

error = 6.25 - 6 = 0.25

So we have

p(\%) =  \frac{0.25}{6.25}  \times 100

We have the final answer as

<h3>4 %</h3>

Hope this helps you

3 0
2 years ago
Suppose total world energy consumption of fossil fuels, equal to 3×1017 kJ/yr, were to be obtained entirely by combustion of pet
Natasha_Volkova [10]

Answer:

it would definitely be wienerballs1977

Explanation:

fossil fuels x (3x1017kJ/yr) equals out to be wienerballs1977.

thx for the challenge !

3 0
2 years ago
How to correctly solve this problem : 4.05Kg+567.95g+100.1g correct and best way
VARVARA [1.3K]
Check attached file for the answer.

7 0
2 years ago
What reaction is depicted by the given equation: Au3+ + 3e− Au
mr Goodwill [35]
Reduction. B is the correct answer
3 0
2 years ago
Read 2 more answers
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