2 years ago

Question 2 (1 point)

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

3 0

4x+8=-x+10.
+1x +1x. =5x+8=10
sorry didn’t know how to put it into words

You might be interested in

If r is the midpoint of qs rs=2x-4, st= 4x-1 and rt = 8x-43 find qs

sammy [17]

Answer:

$QS=68\ units$

Step-by-step explanation:

step 1

Find the value of x

we know that

r is the midpoint of qs

QR=RS

QS=QR+RS------> QS=2RS -----> equation A

RT=RS+ST ----> equation B

see the attached figure to better understand the problem

Substitute the given values in the equation B and solve for x

$8x-43=(2x-4)+(4x-1)$

$8x-43=6x-5$

$8x-6x=43-5$

$2x=38$

$x=19$

step 2

Find the value of RS

$RS=2x-4$

substitute the value of x

$RS=2(19)-4$

$RS=34\ units$

step 3

Find the value of QS

Remember equation A

QS=2RS

$QS=2(34)=68\ units$

6 0

2 years ago

In a shipment of toys from a manufacturer. The probability that a toy is defective is 1/50. If Marie selects 2 toys from a shipm

sukhopar [10]

The probability is 1/2500. (1/50)*(1/50)

7 0

2 years ago

Read 2 more answers

I am factor of 12. The other factor is 3. What number am I

Goryan [66]

12*3= 36

12 and 3 could be factors of 36.

I hope this helped you! <3

8 0

2 years ago

Read 2 more answers

Gino has a stick of pepperoni that is 26 1/2 inches long. He wants to cut 1/2 inch pieces to put on his large pizza. How many pi

ikadub [295]

Answer:57 pieces

Step-by-step explanation:

If the pepperoni is 26 1/2 inches long and he is cutting then 1/2 in slices. You are going to get 2 slices per inch. So multiply 26 x 2 which is 56 then add 1 for the half inch which gives you 57 slices

4 0

2 years ago

Find the general solution of y''' + 6y'' + y' − 34y = 0 if it is known that y1 = e−4x cos(x) is one solution.

SashulF [63]

Answer:

Step-by-step explanation:

Given is a differential equation of III order,

$y''' + 6y'' + y' - 34y = 0$

The characteristic equation would be cubic as

$m^3+6m^2+m-34=0$

By trial and error, we find that

$f(2) = 2^3+6(2^2)+2-34 =0\\$

Thus m=2 is one solution

Since given that $e^{-4x} cos x$ is one solution we get

m = -4+i and hence other root is conjugate $m=-4-i$

Hence general solution would be

$y=Ae^{2x} +e^{-4x} (Bcosx +C sinx)$

3 0

2 years ago