Question 2 (1 point)
1 answer:
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You'll find it easier to understand if you illustrate the problem as what is shown in the attached picture. From the illustration and the problem description, two equations can be formulated:
HJ = 2JK
HJ + JK = HK
2JK + JK = 78
3JK = 78
JK = 78/3
JK = 26
HJ = 2JK
HJ + JK = HK
2JK + JK = 78
3JK = 78
JK = 78/3
JK = 26
We have that
h(t) = –16t²<span> + 14t
using a graph tool
see the attached figure
</span><span>the cricket’s hang time is the difference between point (0,0) and (0.875,0)
</span>(0.875-0)=0.875 sec
the answer is 0.875 sec
h(t) = –16t²<span> + 14t
using a graph tool
see the attached figure
</span><span>the cricket’s hang time is the difference between point (0,0) and (0.875,0)
</span>(0.875-0)=0.875 sec
the answer is 0.875 sec