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lukranit [14]
2 years ago
13

The least-squares regression line Sˆ=0.5+1.1L models the relationship between the listing price and the actual sales price of 12

houses, with both amounts given in hundred-thousands of dollars. Let L represent the listing price and S represent the sales price.
Mathematics
2 answers:
Vlada [557]2 years ago
6 0

Answer:

For each hundred-thousand-dollar increase in the listing price, the sales price is predicted to increase by $110,000.

Step-by-step explanation:

The sales price is not predicted to increase by $1.1; it is predicted to increase by $110,000 because S is measured in hundred-thousands of dollars. The sales price will not decrease by $110,000; it is predicted to increase by $110,000.

irga5000 [103]2 years ago
6 0

Answer:

For each hundred-thousand-dollar increase in the listing price, the sales price is predicted to increase by $110,000.

Step-by-step explanation:

went over it in class

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The Bay Area Online Institute (BAOI) has set a guideline of 60 hours for the time it should take to complete an independent stud
yarga [219]

Answer:

 At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.

Step-by-step explanation:

From the question we are told that

   The  population mean is \mu  =  60 \ hr

    The sample size is  n  =  16

    The  sample mean is  \= x  =  68 \ hr

     The  standard deviation is  \sigma  =  20 \ hr

The  null hypothesis is  H_o  :  \mu  =  60

The  alternative H_a :  \mu >  60

Here we would assume the level of significance of this test to be  

         \alpha  =  5\%  =  0.05

Next we will obtain the critical value of the level of significance from the normal distribution table, the value is    Z_{0.05} =  1.645

  Generally the test statistics  is mathematically represented as

           t =  \frac{ \= x  - \mu}{  \frac{ \sigma }{\sqrt{n} } }

substituting values

           t =  \frac{  68  - 60 }{  \frac{ 20 }{\sqrt{16} } }

          t = 1.6

Looking at the value of t and  Z_{\alpha } we see that t< Z_{\alpha } hence we fail to reject the null hypothesis

   This means that there no sufficient evidence to conclude that it takes more than 60 hours to complete the course

So

   At the 5% level, BAOI can infer that the average time to complete does not exceeds 60 hours.

6 0
2 years ago
The perimeter of a rectangle is 13cm and its width is 11/4. find its length.
enyata [817]
Perimeter = 2 length + 2 width

P = 2(l) + 2(11/4)

13 = 2l +2* \frac{11}{4}

13 = 2l + \frac{2}{1} * \frac{11}{4}

13 = 2l + \frac{22}{4}     (subtract 22/4 from each side)

13 -\frac{22}{4} = 2l

13 -\frac{11}{2} = 2l

\frac{26}{2}  -\frac{11}{2} = 2l

\frac{15}{2}} = 2l

7.5 = 2l    (divide each side by 2)

7.5 ÷ 2 = l

3.75 = l

The answer is 3.75 or 3 \frac{3}{4}


6 0
2 years ago
Theresa has hired Chuck and Diana to paint a fence. Diana can paint 150 fence posts in the same time it takes Chuck to paint 130
Alenkasestr [34]

Answer: Chuck can paint 65 posts per hour.

Step-by-step explanation:

The data we have here is:

Diana can paint 150 fence posts in a time T

Chuck can pint 130 fence posts in a time T.

In one hour, Diana can paint 10 more fence posts than Chuck.

If D is the hourly rate of Daian, and C is the hourly rate for Chuck, we have:

D = 150/T

C = 130/T

D = C + 10

we can replace the last equation in the first one and geT:

C + 10 =150/T

C = 130/T

Now we can replace the bottom equation in the above one:

130/T + 10 = 150/T

10 = 150/T - 130/T =  20/T

T*10 = 20

T = 20/10 = 2

So T is 2 hours, then whe have:

D = 150post/2hours = 75 posts per hour.

C = 130 posts/2hours = 65 posts per hour.

4 0
2 years ago
From Tony's seat in the classroom, his eyes are 1.0 m above ground. On the wall 4.2 m away, he can see the top of a blackboard t
Semmy [17]

Answer:

15 degrees

Step-by-step explanation:

Draw a horizontal segment approximately 4 inches long. Label the right endpoint A and the left endpoint C. Label the length of AC 4.2 meters. That is the horizontal distance between the eye and the blackboard.

At the right endpoint, A, draw a vertical segment going up, approximately 1 inch tall. Label the upper point E, for eye. Label segment EA 1 meter since the eye is 1 meter above ground.

At the left endpoint of the horizontal segment, point C, draw a vertical segment going up approximately 2 inches. Label the upper point B for blackboard. Connect points E and B. Draw one more segment. From point E, draw a horizontal segment to the left until it intersects the vertical segment BC. Label the point of intersection D.

The angle of elevation you want is angle BED.

The length of segment BC is 2.1 meters. The length of segment CD is 1 meter. That means that the length of segment BD is 1.1 meters.

To find the measure of angle BED, we can use the opposite leg and the adjacent leg and the inverse tangent function.

BD = 1.1 m

DE = 4.2 m

tan <BED = opp/adj

tan <BED = 1.1/4.2

m<BED = tan^-1 (1.1/4.2)

m<BED = 15

Answer: 15 degrees

7 0
2 years ago
1. The graph shows the number of miles Peter's car traveled and the gallons of gas used.
steposvetlana [31]

Answer:

  C.  d = 24g

Step-by-step explanation:

The problem boils down to determining the ratio between d and g. That is, for some equation ...

  d = k·g

we want to determine the value of k. Solving the equation for that value, we find ...

  k = d/g

So, we need only to read a point from the graph with sufficient accuracy to determine a good estimate for k.

  (gallons, miles) = (g, d) = (5, 120) is a suitable point

Then ...

  k = d/g = 120/5 = 24

The equation is d = 24g.

4 0
2 years ago
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