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2 years ago

10. Two balls are simultaneously applied with a force of 20 N. One ball has a

Chemistry

1 answer:

Sergeeva-Olga [200]2 years ago

8 0

Answer:

Option C. The one with a mass of 0.3 kg has the greater acceleration.

Explanation:

Let m₁ and m₂ represent the masses of the two balls.

Let a₁ and a₂ represent the acceleration of the two balls.

The following data were obtained from the question:

Force (F) applied = 20 N

Mass 1 (m₁) = 0.3 Kg

Mass 2 (m₂) = 0.4 Kg

Acceleration 1 (a₁) =..?

Acceleration 2 (a₂) =...?

Force (F) = mass (m) × acceleration (a)

F = ma

With the above formula, we can obtain the acceleration of each bass as follow:

For ball with mass 0.3 Kg:

Force (F) applied = 20 N

Mass 1 (m₁) = 0.3 Kg

Acceleration 1 (a₁) =..?

F = m₁ × a₁

20 = 0.3 × a₁

Divide both side by 0.3

a₁ = 20/0.3

a₁ = 66.67 m/s²

For ball will mass 0.4 Kg:

Force (F) applied = 20 N

Mass 2 (m₂) = 0.4 Kg

Acceleration 2 (a₂) =...?

F = m₂ × a₂

20 = 0.4 × a₂

Divide both side by 0.4

a₂ = 20/0.4

a₂ = 50 m/s²

Summary:

Mass >>>>>>>>> Acceleration

0.3 Kg >>>>>>>> 66.67 m/s²

0.4 Kg >>>>>>>> 50 m/s²

From the above illustration, we can see that the ball with mass 0.3 Kg has the highest acceleration.

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For the reaction $PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$ at equilibrium, which statement correctly describes the effects of increasing pressure and adding $PCl_5$ , respectively

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c) Increasing pressure causes shift to products, adding $PCl_5$ causes shift to products.

d) Increasing pressure causes shift to reactants,adding $PCl_5$ causes shift to reactants

Answer: Increasing pressure causes shift to reactants, adding $PCl_5$ causes shift to products.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

a) If the pressure is increased, the volume will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. As the number of moles of gas molecules is lesser at the reactant side. So, the equilibrium will shift in the left direction. i.e. towards reactants.

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