The answer is true because if you multiply 3•(3) is will give you 9 and if you multiply 10•(3) it will give you 30 which gives you both of the sides for the larger one

7 0

2 years ago

Two quadrilaterals are congruent. One has vertices P, N, O, and M, and the other has vertices S, T, V, and U. These correspondin

Bogdan [553]

Answer: $NPOM \cong VUTS$ and $OPNM \cong TVUS$ will be correct.

Explanation:

Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent, where, OM is congruent or equal to TS and $\angle P\cong \angle U$ .

in quadrilaterals NPOM and VUTS-

since, the condition $\angle P = \angle U$

and, side UV=side OM follow for the above quadrilateral. (According to the figure)

then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.

similarly, these two conditions also follow in the case of $OPNM \cong TVUS$

we can understand it by making the figures.

6 0

1 year ago

Read 2 more answers

Select all of the answers below that are equal to B = {John, Paul, George, Ringo, Pete, Stuart}

UNO [17]

Answer:

The correct option is 5) {Paul, Ringo, Pete, John, George, Stuart}.

Step-by-step explanation:

Consider the provided sets:

B = {John, Paul, George, Ringo, Pete, Stuart}

Two sets are equal if all the elements of Sets are same.

Set B has the elements: John, Paul, George, Ringo, Pete and Stuart

Now consider the provided options of sets.

From the provided options of set only option 4 has all the elements of set B but the order is different.

Thus, the correct option is 5) {Paul, Ringo, Pete, John, George, Stuart}.

8 0

2 years ago

Jim Ryan, an owner of a Burger King restaurant, assumes that his restaurant will need a new roof in 7 years. He estimates the ro

Lelu [443]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$9000\\
P=\textit{original amount deposited}\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &7
\end{cases}
\\\\\\
9000=P\left(1+\frac{0.06}{4}\right)^{4\cdot 7}\implies 9000=P(1.015)^{28}\implies \cfrac{9000}{1.015^{28}}=P$

6 0

2 years ago